Compute and plot the derivative of the function f(x) = x³ • Apply the above methodology to compute and plot the derivative of the function f(x) = x³, for x = [-n, n], for n = 5 and 8 In [39]: import matplotlib.pyplot as plt n = 5 r = list (range(-n, n+1)) cubes = [] ## generate the squares using a for loop for value in r: s = value**3 cubes.append(s) slopes = [] first = b = ## generate plot points from existing lists plt.plot(r, cubes, label='function line') plt.plot(r, cubes, 'ro', label = 'function points') plt.plot(r, slopes, label = 'slope line') plt.plot(r, slopes, 'go', label = 'slope points') plt.plot(r, trueslope, label 'true slope') #generate axes Lables plt.ylabel('cubes value') plt.xlabel('integer input') plt.title('cubes plot') plt.legend() # display plot plt.show()

Compute and plot the derivative of the function f(x) = x³ • Apply the above methodology to compute and plot the derivative of the function f(x) = x³, for x = [-n, n], for n = 5 and 8 In [39]: import matplotlib.pyplot as plt n = 5 r = list (range(-n, n+1)) cubes = [] ## generate the squares using a for loop for value in r: s = value**3 cubes.append(s) slopes = [] first = b = ## generate plot points from existing lists plt.plot(r, cubes, label='function line') plt.plot(r, cubes, 'ro', label = 'function points') plt.plot(r, slopes, label = 'slope line') plt.plot(r, slopes, 'go', label = 'slope points') plt.plot(r, trueslope, label 'true slope') #generate axes Lables plt.ylabel('cubes value') plt.xlabel('integer input') plt.title('cubes plot') plt.legend() # display plot plt.show()

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The function interleave_lists in python takes two parameters, L1 and L2, both lists. Notice that the lists may have different lengths. The function accumulates a new list by appending alternating items from L1 and L2 until one list has been exhausted. The remaining items from the other list are then appended to the end of the new list, and the new list is returned. For example, if L1 = ["hop", "skip", "jump", "rest"] and L2 = ["up", "down"], then the function would return the list: ["hop", "up", "skip", "down", "jump", "rest"]. HINT: Python has a built-in function min() which is helpful here. Initialize accumulator variable newlist to be an empty list Set min_length = min(len(L1), len(L2)), the smaller of the two list lengths Use a for loop to iterate k over range(min_length) to do the first part of this function's work. On each iteration, append to newlist the item from index k in L1, and then append the item from index k in L2 (two appends on each iteration). AFTER the loop…
Python|you can use modules if necessary order is a list of pairs in the form of 'X-Y' order = ['A-C', 'A-D', 'A-H', 'A-S', '2-C', '2-D', '2-H', '2-S', '3-C', '3-D', '3-H', '3-S', '4-C', '4-D', '4-H', '4-S', '5-C', '5-D', '5-H', '5-S', '6-C', '6-D', '6-H', '6-S', '7-C', '7-D', '7-H', '7-S', '8-C', '8-D', '8-H', '8-S', '9-C', '9-D', '9-H', '9-S', '10-C', '10-D', '10-H', '10-S', 'J-C', 'J-D', 'J-H', 'J-S', 'Q-C', 'Q-D', 'Q-H', 'Q-S', 'K-C', 'K-D', 'K-H', 'K-S'] Notice that there are 13 X's and each of them is paired with 4 values of Y for better understanding please take reference here Y = ['C','D','H','S']X = ['A', '2', '3', '4', '5', '6', '7', '8', '9', '10', 'J', 'Q', 'K'] 1.) I have a code that prints only the third and the first pair from the list above? Meaning it prints an X with the third and first Y in the list (order). However, It prints with a bracket[] and is separated with quotes ' '{see picture for my output} both needs to be removed. Also it only needs to print the first…
// pre: list != null, list.length > 0 // post: return index of minimum element of array public static int findMin(int[] list) { assert list != null && list.length > 0 : "failed precondition"; int indexOfMin = 0; for(int i = 1; i < list.length; i++) { if(list[i] < list[indexOfMin]) { indexOfMin = i; } } return indexOfMin; } Question: draw DFG from the code above find the all-def/c/p use paths. Generate test cases to test this function using JUnit! (to test all-def/c/p use path)
Write a for loop to print all NUM_VALS elements of vector courseGrades, following each with a space (including the last). Print forwards, then backwards. End with newline. Ex: If courseGrades = {7, 9, 11, 10}, print:7 9 11 10 10 11 9 7 Hint: Use two for loops. Second loop starts with i = courseGrades.size() - 1 (Notes)C++ without using std:: Note: These activities may test code with different test values. This activity will perform two tests, both with a 4-element vector (vector<int> courseGrades(4)). See "How to Use zyBooks".Also note: If the submitted code has errors, the test may generate strange results. Or the test may crash and report "Program end never reached", in which case the system doesn't print the test case that caused the reported message. #include <iostream>#include <vector>using namespace std; int main() { const int NUM_VALS = 4; vector<int> courseGrades(NUM_VALS); int i; for (i = 0; i < courseGrades.size(); ++i) { cin >>…
Write a function called mutate_list() that takes a 2D-list of integers as the input parameter and performs the following mutations: a. any even integer (non-zero) gets divided by 2, b. any odd integer less than 10 gets multiplied by 10, and c. any row (an element of the 2D-list) with less than 5 elements should be padded with zeroes to exactly 5 elements. Sample run, >>> print( mutate_list( [ [1, 2, 3], [20, 3, 40, 5, 60] ] ) ) [[10, 1, 30, 0, 0], [20, 30, 40, 50, 60]] >>> print( mutate_list( [[8,5,7,2],[13,12,9,17,5],[10,20],[1,2,3,4,5,6]] ) ) [[4, 50, 70, 1, 0], [13, 6, 90, 17, 50], [5, 10, 0, 0, 0], [10, 1, 30, 2, 50, 3]]
Write the following function to sort a list of points on their y-coordinates. Each point is a list of two values for x- and y- coordinates. # Returns a new list of points sorted on the y-coordinatesdef sort(points):For example, the points [[4, 2], [1, 7], [4, 5], [1, 2], [1, 1], [4, 1]] will be sortedto [[1, 1], [4, 1], [1, 2], [4, 2], [4, 5], [1, 7]]. Write a test program that displaysthe sorted result for points [[4, 34], [1, 7.5], [4, 8.5], [1, -4.5], [1, 4.5],[4, 6.6]] using print(list).
in python Integer num_samples is read from input, representing the number of data samples to be read from input. List data_list contains the data samples read from the remaining input. For each element in data_list: If the element is greater than 25, output the element followed by ' at index ', the element's index in the list, and ' is flagged'. Otherwise, output the element followed by ' at index ', the element's index in the list, and ' is normal'.
This is for Python version 3.8.5 and please include pseudocode. nums = [8, 15, 6, 17, 33, 20, 14, 9, 12]Write Python code that: uses a function to print the size of the list named nums uses a function to print the largest number in nums prints the element 14 by using its index makes a slice named subnums containing only 33, 20, and 14
PYTHON:My program was supposed to identify the orders of the missing traversal, which is either the preorder or postorder. However, my program only works in identifying the PREORDER. There is something wrong with the function of my POSTORDER. Can you please identify the problem and fix it? I will also add an image below for the expected output and for your reference. Thank you. # Main programinorder_list = []preorder_list = []postorder_list = []n = int(input("How many nodes want to enter? ")) # Methodsdef searchR(arr, x, n): # CHANGED THE NAME OF FUNCTION AS THERE ARE TWO FUNCTION WITH SAME NAME for i in range(n): if (arr[i] == x): return i return -1 def PostOrderT(Ino, preo, n): root = searchR(Ino, preo[0], n) if (root != 0): PostOrderT(Ino, preo[1:n], root) if (root != n - 1): PostOrderT(Ino[root + 1:n], preo[root + 1:n], n - root - 1) print(preo[0], end=" ") # Make new nodeclass newNode: def __init__(self,…
Language: Python 3 Autocomplete Ready O 4. Pair Of Elements having Smallest Absolute Difference 1 v import ast lst = input() 2 3 lst = ast.literal_eval (lst) 4 Given a list of unsorted integers. Find the pair of elements that have the smallest absolute difference between them. If there are multiple pairs, find them all. 5 6 print(smallest_absdiff_pairs(lst)) Implement a function smallest_absdiff_pairs that take a list of numbers and returns a list of pair of elements that have the smallest absolute difference between them. >>> smallest_absdiff_pairs([5, 4, 3, 2]) [(2, 3), (3, 4), (4, 5)] >>> smallest_absdiff_pairs([-20, -3916237, -357920, -3620601, 7374819, -7330761, 30, 6246457, -6461594, 266854, -520, -470]) [(-520, -470), (-20, 30)] >>> smallest_absdiff_pairs([-20, -3916237, -357920, -3620601, 7374819, -7330761, 30, 6246457, -6461594, 266854]) [(-20, 30)]
python wirte a function max_indexes(xs) that inserts a list xs with numbers and returns a list of indexpositions where the list has local maximum values. A local maximum value is a number in the list that has a smaller number before and after. for example in this list has a local maximum at position 2 and 7: [3, 4, 5, 2, 1, 0, 4, 6, 4, 2, 1] Here the function should return [2, 7]
Complete the reverse_list() function that returns a new string list containing all contents in the parameter but in reverse order. Ex: If the input list is: ['a', 'b', 'c'] then the returned list will be: ['c', 'b', 'a'] Note: Use a for loop. DO NOT use reverse() or reversed(). This is my code so far: def reverse_list(letters): for x in (letters): letters.sort(reverse=True) return lettersif __name__ == '__main__': ch = ['a', 'b', 'c'] print(reverse_list(ch)) # Should print ['c', 'b', 'a'] When submitting I get 4/10 and it says: Test input list ['a', 'b', 'c'] returns ['c', 'b', 'a'] Your output reverse_list() function reversed array incorrectly: ['c', 'b', 'a'] reverse_list() function should have returned: ['a', 'b', 'c'] Test input list ['a', 'b', 'c', 'd'], first element of returned list is ['d'] Your output First character of returned array should be a instead of d Test empty input array TypeError: object of type 'NoneType' has no len()