Improve my LeetCode Python Pivot Index CodeAlthough the code itself works, it's not able to work with large arrays as leetcode returns it as "Time Limit Exceeded" since my code takes along time to go over and return the Pivot Index can you help me improve my code so that it return the index. Thank you class Solution:def pivotIndex(self, nums): for i in range(len(nums)): if sum(nums[:i]) == sum(nums[i+1:]): return i return -1 Time Limit ExceededLast executed inputTime Submitted09/26/2022 02:0509/26/2022 02:0109/26/2022 01:4609/26/2022 01:4609/26/2022 01:46E ProblemsDetails >[-470, -906,638, -174, -672, -187,-873, -56... View AlStatusTime Limit ExceededRuntime ErrorRuntime ErrorX Pick OneRuntime MemoryNXAN/AN/AN/AN/AN/ALarpypypypypy< Prev 724/2421 Next >1 ▾2▾PRAFET34▾5 ▾678910class Solution:def pivotIndex(self, nums: List[int]) -> int:Testcase Run Code ResultYour inputOutputAccepted Runtime: 56 msExpectedConsolefor i in range (len (nums)):if sum(nums[:i])return i==return -1▲Debugger[1,7,3,6,5,6]33Use Example Testcasessum(nums [i+1:]):Run Code(?DiffSubmit Given an array of integers nums, calculate the pivot index of this array.The pivot index is the index where the sum of all the numbers strictly tothe left of the index is equal to the sum of all the numbers strictly to theindex's right.If the index is on the left edge of the array, then the left sum isbecause there are no elements to the left. This also applies to the rightedge of the array.Return the leftmost pivot index. If no such index exists, return -1.Example 1:Input: numsOutput: 3=[1,7,3,6,5,6]Explanation:The pivot index is 3.Left sum = nums [0] + nums [1] + nums [2] = 1 + 7 + 3 = 11Right sum = nums[4] + nums [5] = 5 + 6 = 112▾345678 ag4 ▾10▾class Solution:def pivotIndex(self, nums: List[int]) -> int:for i in range (len(nums)):if sum(nums[:i])return iTestcase Run Code ResultYour inputOutputreturn -1Accepted Runtime: 56 msExpectedDebugger[1,7,3,6,5,6]33==sum(nums [i+1:]):Diff

Answered: Improve my LeetCode Python Pivot Index…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Related questions

Concept explainers

Question

Improve my LeetCode Python Pivot Index Code

Although the code itself works, it's not able to work with large arrays as leetcode returns it as "Time Limit Exceeded" since my code takes along time to go over and return the Pivot Index can you help me improve my code so that it return the index. Thank you

class Solution:

def pivotIndex(self, nums):

for i in range(len(nums)):
if sum(nums[:i]) == sum(nums[i+1:]):
return i
return -1

Time Limit Exceeded
Last executed input
Time Submitted
09/26/2022 02:05
09/26/2022 02:01
09/26/2022 01:46
09/26/2022 01:46
09/26/2022 01:46
E Problems
Details >
[-470, -906,638, -174, -672, -187,-873, -56... View Al
Status
Time Limit Exceeded
Runtime Error
Runtime Error
X Pick One
Runtime Memory
NXA
N/A
N/A
N/A
N/A
N/A
Lar
py
py
py
py
py
< Prev 724/2421 Next >
1 ▾
2▾
PRAFET
3
4▾
5 ▾
6
7
8
9
10
class Solution:
def pivotIndex(self, nums: List[int]) -> int:
Testcase Run Code Result
Your input
Output
Accepted Runtime: 56 ms
Expected
Console
for i in range (len (nums)):
if sum(nums[:i])
return i
==
return -1
▲
Debugger
[1,7,3,6,5,6]
3
3
Use Example Testcases
sum(nums [i+1:]):
Run Code
(?
Diff
Submit

Given an array of integers nums, calculate the pivot index of this array.
The pivot index is the index where the sum of all the numbers strictly to
the left of the index is equal to the sum of all the numbers strictly to the
index's right.
If the index is on the left edge of the array, then the left sum is
because there are no elements to the left. This also applies to the right
edge of the array.
Return the leftmost pivot index. If no such index exists, return -1.
Example 1:
Input: nums
Output: 3
=
[1,7,3,6,5,6]
Explanation:
The pivot index is 3.
Left sum = nums [0] + nums [1] + nums [2] = 1 + 7 + 3 = 11
Right sum = nums[4] + nums [5] = 5 + 6 = 11
2▾
3
45678 ag
4 ▾
10
▾
class Solution:
def pivotIndex(self, nums: List[int]) -> int:
for i in range (len(nums)):
if sum(nums[:i])
return i
Testcase Run Code Result
Your input
Output
return -1
Accepted Runtime: 56 ms
Expected
Debugger
[1,7,3,6,5,6]
3
3
==
sum(nums [i+1:]):
Diff

Expert Solution

Overview

In this question we have improve the python code execution for large data.

Let's code

Step by step

Solved in 3 steps with 1 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.

Similar questions