Compound B has a molecular formula of C,H0. What is the Unsaturation Number (UN) or Double-BondEquivalent (DBE)?UN/DBE:Based on the UN/DBE you calculated, could there be a double bond in compound B?yesnoBased on the UN/DBE you calculated, could there be a ring in compound B?yesnoBased on the molecular formula and the UN/DBE you calculated, check all the functional groups that could be present incompound B.O ketoneO benzene ringesteralkyneV alcoholO aldehydeO carboxylic acidO alkenenitrileamineO epoxideV etherO ringExamine the IR spectrum provided for compound B.The peaks below 1500 cannot be used to make any structural assignments because they are in the fingerprint region.There are the two important peaks in this IR spectrum: peak 1 which is 3400 cm-', and peak 2 which is 2950 cm¬1.What is peak 1 most likely due to?What is peak 2 most likely due to?O 0-H or N-HO C-0 or N-OO C-H (sp)O C=0C-H (sp?)О-Hor N-HO C-H (sp³)OC-H (sp²)OC-H (sp³)C=0C-O or N-OС-Н (sp)Earlier, using the molecular formula and the UN/DBE, you came up with a list of functional groups that could be present incompound B. Now, using the IR data you should be able to narrow this list.Check all the functional groups that could be present in compound B.ерохideO alkynealkeneO amineO ringaldehydeO nitrile| esterO ketoneV alcoholO etherO benzene ringO carboxylic acidExamine the 13C spectrum of compound B.Compare the number of signals in the spectrum and the number of carbons from the molecular formula for compound B.Which of the given statements is true?All the carbons are nonequivalent.There is one set of four equivalent carbons.There are two separate sets of equivalent carbons.Evaluate the spectrum for compound A based on what you already know from the UN/DBE and IR spectrum.Is the 13C spectrum consistent with the presence of an alcohol functional group?yesnoExamine the 'H spectrum of compound B.There is a table summarizing the spectral data. Using that data, assign each peak to the type of alkyl group.ppmIntegrationSplittingA3.601 HsingletB3.201 HtripletC1.902HmultipletD0.9012 HdoubletBased on the IR spectrum you determined that there will be an alcohol functional group. Which signal in the 'H spectrumis due to that OH?ABDBased on the carbon spectrum you know that the molecule has a high degree of symmetry. Yet compound B has only oneO. Therefore the OH group and the carbon that it is attached to have to belong in the plane of symmetry. Which 'H signalis due to the hydrogen that is on the same carbon as the OH group?O ABODExamine signal D. It has an integration of 12. How many equivalent methyl (CH,) groups are there in compound B?number of equivalent methyl groups:4Now, you need to arrange the methyl groups in such a way that each of them is bound to a carbon that only has one protonon it.Hint: Calculate how many carbons and hydrogens you have not used yet.What is the name of this alkyl fragment?ethyl grouptert-butyl groupisopropyl groupn-propyl groupO OO O O O O O D O

Answered: Image /qna-images/answer/821427d7-6d3f-4421-8a67-f0bc9baaf231.jpg

Compound B has a molecular formula of C,H0. What is the Unsaturation Number (UN) or Double-Bond Equivalent (DBE)? UN/DBE: Based on the UN/DBE you calculated, could there be a double bond in compound B? yes no Based on the UN/DBE you calculated, could there be a ring in compound B? yes no Based on the molecular formula and the UN/DBE you calculated, check all the functional groups that could be present in compound B. O ketone O benzene ring ester alkyne V alcohol O aldehyde O carboxylic acid O alkene nitrile amine O epoxide V ether O ring O O O O O O O O D O

Compound B has a molecular formula of C,H0. What is the Unsaturation Number (UN) or Double-Bond Equivalent (DBE)? UN/DBE: Based on the UN/DBE you calculated, could there be a double bond in compound B? yes no Based on the UN/DBE you calculated, could there be a ring in compound B? yes no Based on the molecular formula and the UN/DBE you calculated, check all the functional groups that could be present in compound B. O ketone O benzene ring ester alkyne V alcohol O aldehyde O carboxylic acid O alkene nitrile amine O epoxide V ether O ring O O O O O O O O D O

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

3
Organic Chemistry 1. Can you please draw out all five answer choice structures ? Thank you very much
(not use hend raiting)
Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table
SC Question 4 What are the stereochemistries of the two double bonds in the structure below? 0 orlo F2 Bond 1 is E and bond 2 is Z. Both are Z double bonds. Both are E double bonds. Bond 1 is Z and bond 2 is E. 20 F3 DOO 000 F4 EN .. 9/ F5 OCT 1 18 MacBook Air F6 11
From the molecule C7H13N, draw (IF YOU CAN): a)constitutional isomer that has one quarternary carbon b) constitutional isomer that has one tertiary carbon c) constitutional isomer that has only primary and secondary carbons d) constitutional isomer that has one asymmetric carbon
Inspect the structures shown below and select the correct statement. COƏH HN-C-H CH2 ÇOH H2N-C-H CH2 COH HN-C-H CH2 COH HN-C-H Он SH 1 2 4 O #1 and #4 have the S configuration, #2 and #3 have the R configuration. O All structures have the R configuration. O All structures have the S configuration. O #1, #2, and #4 have the S configuration and #3 has the R configuration. O #1 and #4 have the R configuration, #2 and #3 have the S configuration.
Write the IUPAC name of the following compounds. Don’t use CIS/TRANS or E/Z in naming the compounds. NOTE: needs answers immediately. Will send a good rate right away as well.
Check the box under each structure in the table that is an enantiomer of the molecule shown below. If none of them are, check the none of the above box under the table. CI ***OH H Molecule 1 H HO". HO" H Molecule 4 Br 0 CI none of the above Molecule 2 Br H OH 0 Molecule 5 Br Jo OH H 0 Molecule 3 HO H Molecule 6 Cl OH C/*** H U X Ś