Compound A, C14H10, absorbed only 2 equivalents of H2 on catalytic hydrogenation over a Pd/C catalyst to yield compound B, C14H14. On ozonolysis, compound A gave only benzoic acid, C,H,O2. Draw the structure of compound B.
Compound A, C14H10, absorbed only 2 equivalents of H2 on catalytic hydrogenation over a Pd/C catalyst to yield compound B, C14H14. On ozonolysis, compound A gave only benzoic acid, C,H,O2. Draw the structure of compound B.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I cannot figure out the structure for compound B?

Transcribed Image Text:**Text:**
Compound A, C₁₄H₁₀, absorbed only 2 equivalents of H₂ on catalytic hydrogenation over a Pd/C catalyst to yield compound B, C₁₄H₁₄. On ozonolysis, compound A gave only benzoic acid, C₇H₆O₂.
Draw the structure of compound B.
**Explanation:**
This text discusses the transformation of compound A (C₁₄H₁₀) through catalytic hydrogenation and ozonolysis. Initially, compound A undergoes hydrogenation with a palladium on carbon (Pd/C) catalyst, absorbing 2 equivalents of hydrogen gas (H₂) to form compound B (C₁₄H₁₄). This indicates compound A likely has two double bonds that are hydrogenated.
Furthermore, compound A is subjected to ozonolysis, resulting in the formation of benzoic acid (C₇H₆O₂), suggesting it contains one or more benzene rings which cleave during the ozonolysis process.
Students are asked to draw the structure of compound B, considering the conditions and products described.
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