Components Used:PartValuesRI22000R2600 QVsi6VVs23 VTable 11. Hand CalculationAnalyze the circuit in Figure 1. Perform Superposition Analysis, show your steps of calculations clearlyand record your values on Table 2Ir1R1Vs1Vs2Ir2R2 1. Measure the voltage VAB' and current Ir2' due to Vs1 only (Replace Vs2 with a shortcircuit).2. Measure the voltage VAB" and current Ir2" due to Vs2 only (Replace Vs1with a shortcircuit).3. Calculate the total voltage and current by summing the two values togetherDue to Vsi onlyDue to Vs2onlyTotalVAB'VAg"VAB (Vaa' + Vaa")IR2"Irz (Irz' + Ir2")Table 34. For the same Circuit measure VAB and current Ir2 without applying the superposition TheoremTotalVABIR2Table 4

Answered: Image /qna-images/answer/a7d28d87-a3b6-47fe-92a9-2d4e9d4e5857.jpg

Components Used: Part Values R1 22000 R2 600 Q Vsi 6V Vs2 3 V Table 1 1. Hand Calculation Analyze the circuit in Figure 1. Perform Superposition Analysis, show your steps of calculations clearly and record your values on Table 2 IR1 R1 Vs1 Vs2 Ir2 R2

Components Used: Part Values R1 22000 R2 600 Q Vsi 6V Vs2 3 V Table 1 1. Hand Calculation Analyze the circuit in Figure 1. Perform Superposition Analysis, show your steps of calculations clearly and record your values on Table 2 IR1 R1 Vs1 Vs2 Ir2 R2

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Similar questions

What is wrong with this circuit? * R₁10 kn V₁ 24 V D₁ 1N4744A 1 15 V The zener is open. O The zener is shorted or damaged O not enough data O reversed connection of zener diode + 4.790 VR₂ 2.5 k R₁
Determine all the resistor values in figure below. R₁ = 77392. Vs 15.53 mA R₁ 3.64 mA R₂ HI₁ 6.67 mA R3 www R₁ 3.08 mA
Please explain the question step by step and please care to explain the question in detail with your own sentence and explain why you used that formula, calculations, etc. Thanks in advance.
Determine todos los valores de corrientes y tensiones de manera exacta aun si algún transistor esté ensaturation. R1 = 1k R2 = 7K R3 = 1K R4 = 3K
12 = ➖➖➖➖➖➖➖➖* + E Si ✈ D₁ 20 V R₂ 5.6 ΚΩ 3.32 mA 3.12 mA 3.55 mA 3.97 MA What is wrong with this circuit? * - V₁ 24 V R₁10 kn D₁ Si D₂ ID₂ 1N4744A 15 V The zener is open. The zener is shorted or damaged not enough data reversed connection of zener diode R₁ 3.3k92 4.790 1₁ R₂2.5 kn RL
Vcc =16V, R1 = 5600 ohm, R2 = 350000ohm, R3 = 980 B = 80 Calculate, a)Ib b)Vc c)VB d)VCE e)VE
Given a current I3 equals to 5A with a Resistive Load of 10 ohms. Determine the Voltage drop across the 8 hmresistor (R1) and the total Current of the circuit.
Consider the circuit shown in the figure below, If the voltage at point a is 15V and point b is 6V, calculate the current of the 30 resistance. 32 a o 122 412 Oa 6A Ob. 7A Oc. 3A Od 9A
olçpar3.pat A Sesli oku V Ciz 2-In the image, R2 is a resistive sensor in the circuit that changes it's resistance with the x value to be measured (R2=R20(1+ax) a is a contstant and R20=2K6). Digital V Meter is autoranged, has 3 1/2 digits and can have infinite impedance. For DVM Au#+-(%0.05 of value read +%0.04 of level) [V] 2a-If a = 1, x#0 and x = 0,25, what are the values read on the DVM? 2b-lf all resistances used in the circuit has tolerances of 1%, find the absolute uncertainty of read value x= 0 for 95% reliability level. 6V 2k R3 1k4: 1.4k 164
Please help me with this electronic excercise.
Find the equivalent resistance Rab for this circuit
C -Q (A) 0.25 uF 10V 2uF 4uF (B) Figure 3: 3. In Figure 3 the capacitors were discharged before being connected to the battery. (a) In Figure 3A the net positive charge delivered by the battery is +Q1 to C1 and a net negative charge -[Q2 + Q3] is delivered to C2 and C3 [-Q2 is delivered to C2 and -Q3 to C3]. From conservation of charge[net charge is zero since both the battery and the capacitors have a zero net excess charge] and path independence of the electric field[sum of voltages must add up to zero for a closed path or conservation of energy]: Q1 + (-Q2) + (-Q3) = 0 conservation of charge +%-왕-용 (True, False) = 0 conservation of energy +V - = 0 conservation of energy (b) If (a) is true then the charge Q1, Q2 and Q3 follow from above three equations as C1(C2 + C3) V Q2 = Ci + C2 + C3 C1 C3 Ci + C2 + C3 Q1 = Q3 = V, (True, False) C1 + C2 + C3 (c) In Figure 3A the net positive charge delivered by the battery is Qtot = Q1 = C1(C2+C3) v which implies an equivalent capacitance of Qtot…