Component#, Color, Distance component traveled (mm) Distance solvent front traveled (mm), Rf, Possible identityof component000Beta-caroteneChlorophyll aChlorophyll bxanthophyllsFigure 8. TLC chromatogram of the pigments(components) in spinach (example/reference).MSFigure 18. TLC of experimental spinach reference standard(1st, 3rd, and 5th columns) and two unknown plant leaves (2ndand 4th columns).MSActivity #5 (2 pts) Complete Table 5, Components of Unknown Plant Leaves.Use Figure 18 (above) to calculate the Rr value for each component in unknown leaf samples 1 and 2(columns 2 and 4) using the method described above. Assign a possible identity of each pigment in leafsamples 1 and 2 (columns 2 and 4) based on comparison to the spinach reference standard. If the leafsamples contain pigments or spots that do not have comparable spots in the spinach standard, label thesecomponents as "unknown."Table 5. Components of Unknown Plant LeavesRKJCMSRKJCFComponent# ColorDistance componenttraveled (mm)Distance solvent frontRftraveled (mm)Possibleidentityof componentMS

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Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

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mead. Post Lab #2 Smear & Stain Preparation Name: Leidiawa MontaNo Date: 1. Why are thick or dense smears less likely to provide a good smear preparation for microscopic evaluation? Please explain. Becapse, it will diminish the amount ds latcan Pass through by mam 1t difficult to See under the micioscol e, s less liket to Prowde a go image. 2. What could potentially happen if you leave the slide exposed for too long to the open flame? Why do you have to be careful? we can form ring Patterns if we expose the slide for ta0 the flame 3. During the preparation of a smear leading into simple staining of the bacterial culture S. epidermidis you forgot to heat fix the slide. What would you see on this slide as compared to a slide that was properly prepared? Please explain. 4. You partner stained bacterial cells and saw only the background and not the actual cell was stained. Your partner thought this was a mistake. Please explain what type of staining method this is, how it works and why the…
Time point (min) Absorbance of culture at 660nm Approximate cell concentration Approximate # cells in 1mL extract 0 0.298 1.49 x 108 cells/mL 1.49 x 108 cells 10 0.316 1.58 x 108 cells/mL 1.58 x 108 cells 20 0.374 1.87 x 108 cells/mL 1.87 x 108 cells 30 0.429 2.145 x 108 cells/mL 2.145 x 108 cells 40 0.512 2.56 x 108 cells/mL 2.56 x 108 cells 50 0.544 2.72 x 108 cells/mL 2.72 x 108 cells 60 0.607 3.035 x 108 cells/mL 3.035 x 108 cells a. Using these data, prepare a growth curve of this strain ofEscherichia coli (E. coli).b. Estimate the doubling time for this strain of E. Coli. Clearly showhow you estimated this value from the empirical data presented.
do methodologies preparation of the following 6 solutions (Broth LB, LB Agar, Potato-Dextrose Agar, LB-Dextrose Broth, Saline solution 0.85%, Glycerol 80%). Include photos or schematics.
Example of a Protein Purification Scheme: Purification of the Enzyme Xanthine Dehydrogenase from a Fungus Volume Total Total Specific Percent Fraction (mL) Protein (mg) Activity Activity Recovery 1. Crude extract 2. Salt precipitate 3. Ion-exchange chromatography |4. Molecular-sieve chromatography 5. Immunoaffinity chromatography 3,800 22,800 2,460 0.108 100 165 2,800 1,190 0.425 48 65 100 720 7.2 29 40 14.5 23 1.8 275 152.108 11 Calculate the specific activity of step#4. Note that percent recovery=% Yield.
50 mg/50 ml kinetin stock is available You need 2.5 mg/l kn for Ms media calculate amount of kn is required? Explain the role of surface sterilising chemicals in aseptic culture initiation and function of sucrose in MS medium?
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C. Spectrophotometric Measurements of the Hill Reaction 1. Place 15 mL of the 0.05-mg chlorophyll/ mL suspension in a test tube. Wrap the tube with aluminum foil and chill in an ice bucket. This is the source of unheated chloroplasts. 2. Place the remaining 10 mL of the 0.05-mg chlorophyll/mL suspension in a test tube and heat until boiling using an alcohol lamp. Heating inactivates the chloroplasts. Stand the heated mixture for 5 min. to allow the debris to settle.
REMOVAL OF WATER FROM MICROBIAL CELLS USING FREEZE DRYING METHOD. Before starting the freeze-drying process, the weight of the test tube, Wi which is 15.33g and test tube with microbial cell pellets, Ww which is 34.94g were weighed using an electronic balance. Plus, final weight of the beaker with test tube and cells is 70.35g. Then, the average amount of water removal and average cell yield were calculated by using the formulas given which were 9.81g and 0.5001. As a conclusion, there was 9.81g of water had been removed by using the technique freeze-drying for 24 hours by using a freeze dryer. Question: 1.From this statement, please explain what process actually has happened during this freeze-drying method. 2.Make a clear conclusion that can made from this experiment.(explain briefly)
Match inhibitors, selective ingredients, pH indicators and other components to correct medium phenol red pH indicator [ Choose ] [Choose] mannitol Мас Sabouraud Agar 7.5 g NaCI/100 ml inhibitor Blood agar MSA low pH, high dextrose concentration [ Choose ] inhibitors neutral red pH indicator [ Choose ] crystal violet and bile salt inhibitors [ Choose] no inhibitors [Choose ] lactose as only sugar in medium [ Choose ]
CLEARING AGENT Give the COMPOSITION of the ff. Clearing agent: 1. Xylene2.Toluene3.Benzene4.Chloroform5.Cedarwood oil6. Aniline Oil7. Clove oil8. Carbon tetrachloride
SDS-PAGE reagents that play a role in formation of the gel only are(Select all that applies) Beta-Mercaptoethanol Bromophenol blue APS Heat Sodium Dodecyl Sulfate Bis-acrylamide Acrylamide TEMED
please give complete table solution i will thumbs up surely

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