Complete this program that reads an integer n and prints the following diamond pattern with 2 *n - 1 asterisks at its widest point. This is the pattern when n is 3:
Complete this program that reads an integer n and prints the following diamond pattern with 2 *n - 1 asterisks at its widest point. This is the pattern when n is 3:
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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how to solve this problem, really need help, please.
Complete this program that reads an integer n and prints the following diamond pattern with 2 * n - 1 asterisks at its widest point. This is the pattern when n is 3:
--*--
-***-
*****
-***-
--*--
![Complete this program that reads an integer n and prints the following diamond pattern with 2 * n - 1 asterisks at its widest point. This is the
pattern when n is 3:
prog.cpp
1#include <iostream>
2 #include <cstdlib>
4 using namespace std;
Eint main()
int n;
cin >> n;
// Draw top triangle
for (int left_stars = 0; left_stars < n; left_stars++)
{
for (int column = 0; column < 2 * n - 1 ; column++)
{
1
1
1
int first star = n
1 - left stars ;
int last star = n - 1 + left stars;
if (column < first star || column > last star)
{
cout << "-":
}
else
{
cout <« "*";
}
}
cout << endl;
}
// Draw bottom triangle
return 0;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbba9d0b3-d893-41fb-b061-e9962d9a1417%2F35deaeda-ce94-4231-af4d-cb9eb2da4b92%2Fccagrjz_processed.png&w=3840&q=75)
Transcribed Image Text:Complete this program that reads an integer n and prints the following diamond pattern with 2 * n - 1 asterisks at its widest point. This is the
pattern when n is 3:
prog.cpp
1#include <iostream>
2 #include <cstdlib>
4 using namespace std;
Eint main()
int n;
cin >> n;
// Draw top triangle
for (int left_stars = 0; left_stars < n; left_stars++)
{
for (int column = 0; column < 2 * n - 1 ; column++)
{
1
1
1
int first star = n
1 - left stars ;
int last star = n - 1 + left stars;
if (column < first star || column > last star)
{
cout << "-":
}
else
{
cout <« "*";
}
}
cout << endl;
}
// Draw bottom triangle
return 0;
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