Complete the table for the given values of x. Then use the table to solve the given equation numerically. Complete the table below. X 0. 1 4. - 4x + 12 = 4 4x+ 12 12 - The solution is x =

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Question
### Solving Linear Equations Using a Table

In this exercise, we solve the linear equation \(-4x + 12 = 4\) numerically by completing a table for the given values of \(x\). Follow the steps below to fill in the table and find the solution for \(x\).

#### Equation to Solve:
\[
-4x + 12 = 4
\]

#### Steps:
1. Substitute different values of \(x\) into the equation.
2. Record the results in the provided table.
3. Identify the value of \(x\) that satisfies the equation.

#### Table to Fill:
\[
\begin{array}{|c|c|c|c|c|c|}
\hline
x & 0 & 1 & 2 & 3 & 4 \\
\hline
-4x + 12 & 12 & \_ & \_ & \_ & \_ \\
\hline
\end{array}
\]

#### Detailed Explanation:
- For \(x=0\): 
  \[
  -4(0) + 12 = 12
  \]

Next, calculate the values for \(x=1, 2, 3, 4\):

- For \(x=1\): 
  \[
  -4(1) + 12 = 8
  \]

- For \(x=2\): 
  \[
  -4(2) + 12 = 4
  \]

- For \(x=3\): 
  \[
  -4(3) + 12 = 0
  \]

- For \(x=4\): 
  \[
  -4(4) + 12 = -4
  \]

#### Completed Table:
\[
\begin{array}{|c|c|c|c|c|c|}
\hline
x & 0 & 1 & 2 & 3 & 4 \\
\hline
-4x + 12 & 12 & 8 & 4 & 0 & -4 \\
\hline
\end{array}
\]

#### Identify the Solution:
Now, look for the value in the table where \(-4x + 12 = 4\):
- When \(x = 2\), \(-4x +
Transcribed Image Text:### Solving Linear Equations Using a Table In this exercise, we solve the linear equation \(-4x + 12 = 4\) numerically by completing a table for the given values of \(x\). Follow the steps below to fill in the table and find the solution for \(x\). #### Equation to Solve: \[ -4x + 12 = 4 \] #### Steps: 1. Substitute different values of \(x\) into the equation. 2. Record the results in the provided table. 3. Identify the value of \(x\) that satisfies the equation. #### Table to Fill: \[ \begin{array}{|c|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline -4x + 12 & 12 & \_ & \_ & \_ & \_ \\ \hline \end{array} \] #### Detailed Explanation: - For \(x=0\): \[ -4(0) + 12 = 12 \] Next, calculate the values for \(x=1, 2, 3, 4\): - For \(x=1\): \[ -4(1) + 12 = 8 \] - For \(x=2\): \[ -4(2) + 12 = 4 \] - For \(x=3\): \[ -4(3) + 12 = 0 \] - For \(x=4\): \[ -4(4) + 12 = -4 \] #### Completed Table: \[ \begin{array}{|c|c|c|c|c|c|} \hline x & 0 & 1 & 2 & 3 & 4 \\ \hline -4x + 12 & 12 & 8 & 4 & 0 & -4 \\ \hline \end{array} \] #### Identify the Solution: Now, look for the value in the table where \(-4x + 12 = 4\): - When \(x = 2\), \(-4x +
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