Use the first table to write the equation being solved. Then use the second table to solve the equation. Y1= 4(x- 3) Y2=4(2-4x) Y2 56 -2 |- 20 Y1 - 3 -24 40 - 16 24 - 12 8 -1 -8- 2 - 4 3 0 -8 - 24 -40

Q: Put the equation y = x² + 8x +7 into the form y = (x - h)²+k:

A:

Q: y= -2x - 4 If x has a value of 4, what would the value of y be?

A: Let we are given - y= f(x) If x=a then y = f(a)

Q: x+2S 3x 16 R. 40

A:

Q: 2x + 3y = -9 4x + 2y = 9 What number would you multiply the top equation by to eliminate the x…

A: One of the way for eliminating one of the variable is, first we look for the variable with same…

Q: The equation is 6n-3, not 6n-1

A:

Q: Make x the subject of the formula- y = (4x+7)/5

A: It is simple calculation.

Q: How do you solve  (a+ 3b)x + (a+3b)y

A: In this question , we can solve the given expression. Firstly solve the brackets that is multiply by…

Q: 13 2y + 3 x - 4

A: To find the value of .

Q: 2x3 +x+18 =0

A: The given function is of degree 3 so, it has three roots real or complex.   Here we have to find…

Q: 3x2-2x+2=0

A:

Q: Hanger A 2x + 10 = 2y + 5

A:

Q: PQ equals 3X +14 and QR equals 7X -10 find X

A: solution:Given: PQ=3X+14QR=7X-10Explanation:Assuming that PQ and PR are equal, it means…

Q: 3x + x + x + x - 3 - 2 = 7 + x + x   What is the value of x?

A: We have to find the value of x.

Q: 6r2+7r-55=0

A: Given the quadratic equation  6r2+7r-55=0 To solve the equation  By using quadratic formula,

Q: graoh the equation, 2y+8x=10

A:

Q: 1. Find the value of x. (3x + 16) (8r + 3)* (10x- 28)

A:

Q: 6x2-2x+7=0

A: We have to use quadratic formula with a=6, b=-2, c=7

Q: 3(8n-4)-6(6-8n)=-48

A: Given: -3(8n-4)-6(6-8n)=-48

Q: -2 (x - 8) + 4x = -12

A: Answer is-  -14.

Q: -7|6x - 9 | +18=18

A: Solve for the x

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.