A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.5%), Married (54.7%), Widowed (2.6%), Divorced (11.2%). The table below shows the results of a random sample of 1768 adult men from California. Test the claim that the distribution from California is as expected at the αα = 0.05 significance level.Complete the table by filling in the expected frequencies. Round to the nearest whole number:Frequencies of Marital StatusOutcomeFrequencyExpected FrequencyNever Married544 Married976 Widowed62 Divorced186 What is the correct statistical test to use?Select an answer Independence Paired t-test Goodness-of-Fit Homogeneity What are the null and alternative hypotheses?H0:H0: Marital status and residency are dependent.The distribution of marital status in California is not the same as it is nationally.The distribution of marital status in California is the same as it is nationally.Marital status and residency are independent.H1:H1: The distribution of marital status in California is the same as it is nationally.Marital status and residency are independent.Marital status and residency are dependent.The distribution of marital status in California is not the same as it is nationally.The degrees of freedom = The test-statistic for this data = (Please show your answer to three decimal places.)The p-value for this sample = (Please show your answer to four decimal places.) The p-value is Select an answer less than (or equal to) greater than αα Based on this, we should Select an answer reject the null accept the null fail to reject the null Thus, the final conclusion is...There is sufficient evidence to conclude that marital status and residency are dependent.There is sufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally.There is insufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally.There is insufficient evidence to conclude that marital status and residency are dependent.There is sufficient evidence to conclude that the distribution of marital status in California is the same as it is nationally.

As per our guidelines, we are only allowed to answer three sub-parts 1) Observed Expected Proportion Expected Value Difference Difference Sq. Diff. Sq. / Exp Fr. Never Married 544 0.32 (556.92) 556.92 -12.92 166.93 0.30 Married 976 0.55 (967.1) 967.1 8.90 79.28 0.08 Widowed 62 0.03 (45.97) 45.97 16.03 257.03 5.59 Divorced 186 0.11 (198.02) 198.02 -12.02 144.38 0.73 Total 6.702What is the correct statistical test to use?Select an answer Independence Paired t-test Goodness-of-Fit Homogeneity Here we will use Chi-Square Goodness of Fit Homogeneity Test A Chi-Square for goodness of fit test is a test used to assess whether the observed data can be claimed to reasonably fit the expected data. Sometimes, a Chi-Square test for goodness of fit is referred as a test for multi-nomial experiments, because there is a fixed number of N categories, and each of the outcomes of the experiment falls in exactly one of those categories. 3) What are the null and alternative hypotheses?Null : H0: The distribution of marital status in California is the same as it is nationally Alternate : H1: The distribution of marital status in California is not the same as it is nationally.4) The degrees of freedom = The distribution of the test statistic is the Chi-Square distribution, with n-1 degrees of freedom, where n is the number of categories Here number of categories = 4 Degrees of Freedom = n -1 = 35) The test-statistic for this data = (Please show your answer to three decimal places.) The formula for a Chi-Square statistic is χ2=∑i=1n(Oi−Ei)2Ei\chi^2 = \sum_{i=1}^n \frac{(O_i-E_i)^2 }{E_i} χ2 = 6.702 (In the above table, it is calculated)

Answered: Complete the table by filling in the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A recent national report states the marital status distribution of the male population age 18 or older is as follows: Never Married (31.5%), Married (54.7%), Widowed (2.6%), Divorced (11.2%). The table below shows the results of a random sample of 1768 adult men from California. Test the claim that the distribution from California is as expected at the αα = 0.05 significance level.

Complete the table by filling in the expected frequencies. Round to the nearest whole number:
Frequencies of Marital Status

Outcome Frequency Expected Frequency

Never Married 544

Married 976

Widowed 62

Divorced 186
What is the correct statistical test to use?
Select an answer Independence Paired t-test Goodness-of-Fit Homogeneity
What are the null and alternative hypotheses?
H0:H0:
- Marital status and residency are dependent.
- The distribution of marital status in California is not the same as it is nationally.
- The distribution of marital status in California is the same as it is nationally.
- Marital status and residency are independent.
H1:H1:
- The distribution of marital status in California is the same as it is nationally.
- Marital status and residency are independent.
- Marital status and residency are dependent.
- The distribution of marital status in California is not the same as it is nationally.
The degrees of freedom =
The test-statistic for this data = (Please show your answer to three decimal places.)
The p-value for this sample = (Please show your answer to four decimal places.)
The p-value is Select an answer less than (or equal to) greater than αα
Based on this, we should Select an answer reject the null accept the null fail to reject the null
Thus, the final conclusion is...
- There is sufficient evidence to conclude that marital status and residency are dependent.
- There is sufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally.
- There is insufficient evidence to conclude that the distribution of marital status in California is not the same as it is nationally.
- There is insufficient evidence to conclude that marital status and residency are dependent.
- There is sufficient evidence to conclude that the distribution of marital status in California is the same as it is nationally.

Outcome	Frequency	Expected Frequency
Never Married	544
Married	976
Widowed	62
Divorced	186

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