Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side. sec z- cot z- 1= cot? z Steps: sec z cot a - 1 cotz
Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side. sec z- cot z- 1= cot? z Steps: sec z cot a - 1 cotz
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![3:53 0 A A A
O * *I 25%
illeenisd.schoology.com
13
2 of 5
Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side.
sec? z · cot? r –1 = cot? z
Steps:
sec' z. cot' - 1
= cot2 a
: (1 sin? z) - sin² z
cus
cat a
:: cus
sin" a
: cos' a. sin
* cse?
1
1
cos z (sin r-cus' 2)
sin
cas
Nin
COs
cori sin? r
1 cos + sin a
! cos +
1
cas
sin a
cos 2
sima
cos
CoS I
sin a
Next
+
II](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F197f2839-92ff-45cd-80af-739d64e8018a%2Fef939903-a14e-4c50-bc59-ce1ded0feffd%2Fnhk9u8_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3:53 0 A A A
O * *I 25%
illeenisd.schoology.com
13
2 of 5
Complete the steps by applying trig identities to show that the left hand side of the equation is equivalent to the right hand side.
sec? z · cot? r –1 = cot? z
Steps:
sec' z. cot' - 1
= cot2 a
: (1 sin? z) - sin² z
cus
cat a
:: cus
sin" a
: cos' a. sin
* cse?
1
1
cos z (sin r-cus' 2)
sin
cas
Nin
COs
cori sin? r
1 cos + sin a
! cos +
1
cas
sin a
cos 2
sima
cos
CoS I
sin a
Next
+
II
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