9) Choose the correct answer. Paul wants to order flowers for Mother's Day and can choose any number of roses and lilies for his mother's flower arrangement. He has a maximum of $50 to spend. Each stem of lilies costs $3.00, and roses cost $3.50 each. Which inequality represents the situation? Let the number of lilies = z and the number of roses = y. 3r – 3.50y > 50 3.50z - 3y 2 50 3x + 3.50y < 50 3x + 3.50y < 50
9) Choose the correct answer. Paul wants to order flowers for Mother's Day and can choose any number of roses and lilies for his mother's flower arrangement. He has a maximum of $50 to spend. Each stem of lilies costs $3.00, and roses cost $3.50 each. Which inequality represents the situation? Let the number of lilies = z and the number of roses = y. 3r – 3.50y > 50 3.50z - 3y 2 50 3x + 3.50y < 50 3x + 3.50y < 50
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter7: Percents
Section: Chapter Questions
Problem 5PTTS
Related questions
Question
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Choose the correct answer.
![9) Choose the correct answer.
Paul wants to order flowers for Mother's Day and can choose any number of roses and
lilies for his mother's flower arrangement. He has a maximum of $50 to spend. Each
stem of lilies costs $3.00, and roses cost $3.50 each. Which inequality represents the
situation? Let the number of lilies = z and the number of roses = y.
3r – 3.50y > 50
3.50z - 3y 2 50
3x + 3.50y < 50
3x + 3.50y < 50](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6889a80a-330d-46f0-b9b2-fdbfba403cd3%2Fb84b3608-dbb2-462a-ad03-5abb523441b7%2Fs3z94qk_processed.png&w=3840&q=75)
Transcribed Image Text:9) Choose the correct answer.
Paul wants to order flowers for Mother's Day and can choose any number of roses and
lilies for his mother's flower arrangement. He has a maximum of $50 to spend. Each
stem of lilies costs $3.00, and roses cost $3.50 each. Which inequality represents the
situation? Let the number of lilies = z and the number of roses = y.
3r – 3.50y > 50
3.50z - 3y 2 50
3x + 3.50y < 50
3x + 3.50y < 50
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