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Complete the proof of (1) (2) (3) (4) *Note • The order of hypotheses matters, ensure in (3) that hypothesis (1) is A and hypothesis (2) is B • There are more options to choose from than needed, and you can use any option as many times as you wish (or not at all) фху ^ (∀x)x = y P(x)x=y (x)x=y (hypothesis) (hypothesis) ( (1), (2), A, B + A^B) ((3), gen, hypothesis ok x dnof in (1) and (2)) pxy, (Vx)x= y (Vx)(xy^(x)x = y) oxy (x) (p(x)x= y) p. (x)x=(x) (p(x)x=y) Р

Complete the proof of (1) (2) (3) (4) *Note • The order of hypotheses matters, ensure in (3) that hypothesis (1) is A and hypothesis (2) is B • There are more options to choose from than needed, and you can use any option as many times as you wish (or not at all) фху ^ (∀x)x = y P(x)x=y (x)x=y (hypothesis) (hypothesis) ( (1), (2), A, B + A^B) ((3), gen, hypothesis ok x dnof in (1) and (2)) pxy, (Vx)x= y (Vx)(xy^(x)x = y) oxy (x) (p(x)x= y) p. (x)x=(x) (p(x)x=y) Р

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Complete the proof of (1) (2) (3) (4) *Note • The order of hypotheses matters, ensure in (3) that hypothesis (1) is A and hypothesis (2) is B • There are more options to choose from than needed, and you can use any option as many times as you wish (or not at all) P^ (x)x=y (Vx)X = Y (hypothesis) (hypothesis) ( (1), (2), A, B = A^B) ( (3), gen, hypothesis ok x dnof in (1) and (2)) oxy, (x)x = y + (x)(xy^ (\x)x = y) фху (x)^(x)x = y) p(x)x=(x)( ^ (x)x = y) oxy(x)x=y р
Transcribed Image Text:Complete the proof of (1) (2) (3) (4) *Note • The order of hypotheses matters, ensure in (3) that hypothesis (1) is A and hypothesis (2) is B • There are more options to choose from than needed, and you can use any option as many times as you wish (or not at all) P^ (x)x=y (Vx)X = Y (hypothesis) (hypothesis) ( (1), (2), A, B = A^B) ( (3), gen, hypothesis ok x dnof in (1) and (2)) oxy, (x)x = y + (x)(xy^ (\x)x = y) фху (x)^(x)x = y) p(x)x=(x)( ^ (x)x = y) oxy(x)x=y р
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