4) (2m-16)=(2m + 4) m-16= m+ 4/3 -16 = 2m -28 m= -7 || +3 m 4

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Question 3

Solve the equation:

\[ 4 \cdot \frac{1}{3}(2m - 16) = \frac{1}{3}(2m + 4) \]

**Solution Steps:**

1. Distribute and simplify both sides:
   \[
   \frac{2}{3}m - \frac{16}{3} = \frac{2}{3}m + \frac{4}{3}
   \]

2. Eliminate \(\frac{2}{3}m\) from both sides:
   \[
   -\frac{16}{3} = \frac{4}{3}
   \]

3. Combine like terms:
   \[
   -28 = -\frac{4}{3}m
   \]

4. Solve for \(m\):
   \[
   m = -7
   \]
Transcribed Image Text:### Question 3 Solve the equation: \[ 4 \cdot \frac{1}{3}(2m - 16) = \frac{1}{3}(2m + 4) \] **Solution Steps:** 1. Distribute and simplify both sides: \[ \frac{2}{3}m - \frac{16}{3} = \frac{2}{3}m + \frac{4}{3} \] 2. Eliminate \(\frac{2}{3}m\) from both sides: \[ -\frac{16}{3} = \frac{4}{3} \] 3. Combine like terms: \[ -28 = -\frac{4}{3}m \] 4. Solve for \(m\): \[ m = -7 \]
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