Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
Related questions
Question
![### Question 3
Solve the equation:
\[ 4 \cdot \frac{1}{3}(2m - 16) = \frac{1}{3}(2m + 4) \]
**Solution Steps:**
1. Distribute and simplify both sides:
\[
\frac{2}{3}m - \frac{16}{3} = \frac{2}{3}m + \frac{4}{3}
\]
2. Eliminate \(\frac{2}{3}m\) from both sides:
\[
-\frac{16}{3} = \frac{4}{3}
\]
3. Combine like terms:
\[
-28 = -\frac{4}{3}m
\]
4. Solve for \(m\):
\[
m = -7
\]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fbd5c2cde-8895-43a3-8db4-0ce93c5f2f01%2F2e6430d6-3bb7-4744-89d0-5bc27b940d4d%2Fnz09i3t_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Question 3
Solve the equation:
\[ 4 \cdot \frac{1}{3}(2m - 16) = \frac{1}{3}(2m + 4) \]
**Solution Steps:**
1. Distribute and simplify both sides:
\[
\frac{2}{3}m - \frac{16}{3} = \frac{2}{3}m + \frac{4}{3}
\]
2. Eliminate \(\frac{2}{3}m\) from both sides:
\[
-\frac{16}{3} = \frac{4}{3}
\]
3. Combine like terms:
\[
-28 = -\frac{4}{3}m
\]
4. Solve for \(m\):
\[
m = -7
\]
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