Complete the if-else statement to print 'LOL means laughing out loud' if user_tweet contains 'LOL' Sample output with input: 'I was LOL during the whole movie!" LOL means laughing out loud.

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
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Is there a way to make an abbreviation using  if else statement in pyhton there's a sample below

### Using If-Else Statements in Python

This exercise demonstrates how to use an if-else statement to check if a specific substring is present within a given string and print an appropriate message.

#### Task

Complete the if-else statement to print "LOL means laughing out loud" if `user_tweet` contains the substring "LOL".

#### Sample Output

For the input: 
```
'I was LOL during the whole movie!'
```
The output should be: 
```
LOL means laughing out loud.
```

#### Code Explanation

Below is a template for the task:

```python
user_tweet = input()

''' Your solution goes here '''

print('LOL means laughing out loud.')
else:
    print('No abbreviation.')
```

#### Steps to Complete the Solution

1. Use an if statement to check if "LOL" is in `user_tweet`.
2. Fill in the missing condition inside the if statement on line 3.

### Example Solution

```python
user_tweet = input()

if 'LOL' in user_tweet:
    print('LOL means laughing out loud.')
else:
    print('No abbreviation.')
```

In this solution:
- The if statement checks if the string "LOL" is present in the `user_tweet` input.
- If "LOL" is found, it prints "LOL means laughing out loud."
- Otherwise, it prints "No abbreviation."
Transcribed Image Text:### Using If-Else Statements in Python This exercise demonstrates how to use an if-else statement to check if a specific substring is present within a given string and print an appropriate message. #### Task Complete the if-else statement to print "LOL means laughing out loud" if `user_tweet` contains the substring "LOL". #### Sample Output For the input: ``` 'I was LOL during the whole movie!' ``` The output should be: ``` LOL means laughing out loud. ``` #### Code Explanation Below is a template for the task: ```python user_tweet = input() ''' Your solution goes here ''' print('LOL means laughing out loud.') else: print('No abbreviation.') ``` #### Steps to Complete the Solution 1. Use an if statement to check if "LOL" is in `user_tweet`. 2. Fill in the missing condition inside the if statement on line 3. ### Example Solution ```python user_tweet = input() if 'LOL' in user_tweet: print('LOL means laughing out loud.') else: print('No abbreviation.') ``` In this solution: - The if statement checks if the string "LOL" is present in the `user_tweet` input. - If "LOL" is found, it prints "LOL means laughing out loud." - Otherwise, it prints "No abbreviation."
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