Complete the following difference equation problem. Y++2 - 4Yt+1 + 4Y = 2(2*) + t² Step 1: Y+2 – 4Y++1+ 4Y; = 0 r2 – 4r + 4 = 0 (r – 2)(r – 2) = 0 Hence roots would be r, = 2 and r2 = 2 since the roots are real and equal, we use the homogenous equation Yn = (A+ Bt)2² Step 2: Particular solution
Complete the following difference equation problem. Y++2 - 4Yt+1 + 4Y = 2(2*) + t² Step 1: Y+2 – 4Y++1+ 4Y; = 0 r2 – 4r + 4 = 0 (r – 2)(r – 2) = 0 Hence roots would be r, = 2 and r2 = 2 since the roots are real and equal, we use the homogenous equation Yn = (A+ Bt)2² Step 2: Particular solution
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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The problem is partially completed, make corrections (if any) and complete. It is a Difference equation using an auxiliary equation (homogenous formula for the right-hand side) and trial and error ((nonhomogenous) for the left-hand side. there is an image a sa guide
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