The data provided give the number of standby hours based on total staff present, X₁, and remote hours, X₂. Perform a multiple regression analysis using the dataprovided and determine the VIF for each independent variable in the model. Is there reason to suspect the existence of collinearity?Click the icon to view the data.Determine the VIF for each independent variable in the model.|VIF ₂2 =VIF₁ =(Round to three decimal places as needed.)Is there reason to suspect the existence of collinearity?OA. No. The VIF for each independent variable is less than 5.B. Yes. The VIF for each independent variable is greater than 5.OC. No. The VIF for each independent variable is greater than 5.OD. Yes. The VIF for each independent variable is less than 5.wwwwwwwTable of DataStandby Total StaffHours Present245330274358195197117153115275200236336339321303286329352323RemoteHours417655524385349350388153278479PrintDone

The data on Stands-by hours based on total staff present and remotes hours are given below,SR…

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Refer to the data set: x -1 1 -2 3 0 2 y 9 2 15 1 4 1.5 Part a: Make a scatterplot and determine which type of model best fits the data.Part b: Find the regression equation, round decimals to one place.Part c: Use the equation from Part b to determine y when x = 5.
Calculate the least square regression equation for the data. Include the slope and y intercept. Round to the nearest hundredth.
Please give solution in correct and step by step detailed format thanku
Complete the statement. and the symbol for the y' intercept is y a b For a regression line in statistics, the symbol for the slope is m
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 40 inches. Is the result close to the actual weight of 352 pounds? Use a significance level of 0.05. Chest size (inches) *Weight (pounds) 44 54 328 528 41 55 39 51 418 580 296 503 Click the icon to view the critical values of the Pearson correlation coefficient r. - What is the regression equation? x (Round to one decimal place as needed.)
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 57 inches. Is the result close to the actual weight of 476 pounds? Use a significance level of 0.05. 44 Chest size (inches) Weight (pounds) 58 48 51 58 60 425 266 347 453 282 408 Click the icon to view the critical values of the Pearson correlation coefficient r. ..... What is the regression equation? y=+x (Round to one decimal place as needed.) Activate Windows View an example Get more help- Help me solve this O Type here to search hp delete insert prt sc f12 f1o fg 1 f7 f6 f5 f3 米 IOI f1 esc hom backspace 6. L. 4 U E R tab F G J. A caps lock pause 00 9, %24 3. %23
Consider the regression équation In =3.94+0.4X₁₁ +0.7X₂- a. Predict the value of Y when X₁ =7.4 and X₂ = 5.2. b. Interpret the meaning of the regression coefficients 100 b,, and 100-b₂. a. The predicted value of Y is (Type an integer or decimal rounded to two decimal places as needed.) b. Choose the correct answer below. OA. Holding constant the other variables, for every one unit increase in X, or X₂, the value of Y increases by b, or by percent, respectively. B. Holding constant the other variables, for every one percent increase in X, or X₂, the value of Y increases by b, or b₂ percent, respectively. C. Holding constant the other variables, for every one unit increase in X, or X₂, the value of Y increases by 100 b, or 100-b₂ percent, respectively. OD. Holding constant the other variables, for every one percent increase in X, or X₂, the value of Y increases by b, or b₂ units, respectively. OE. For every decrease of one unit of In Y, holding bo constant, the estimated change in X, or…
The data show the chest size and weight of several bears. Find the regression equation, letting chest size be the independent (x) variable. Then find the best predicted weight of a bear with a chest size of 63 inches. Is the result close to the actual weight of 522 pounds? Use a significance level of 0.05. Chest size (inches) 58 50 65 59 59 48 D 414 312 499 450 456 260 Weight (pounds) Click the icon to view the critical values of the Pearson correlation coefficient r. What is the regression equation? y=+x (Round to one decimal place as needed.) What is the best predicted weight of a bear with a chest size of 63 inches? The best predicted weight for a bear with a chest size of 63 inches is pounds. (Round to one decimal place as needed.) Is the result close to the actual weight of 522 pounds? O A. This result is not very close to the actual weight of the bear. O B. This result is exactly the same as the actual weight of the bear. O C. This result is close to the actual weight of the…
Use the data in the given table to fill in the missing coefficients. Round your answers to 3 decimal places. x y 7 9.251 11.5 13.308 16 17.366 20.5 21.641 25 26.52 29.5 29.537 34 34.623 y=y= xx +
solve a,b and c given in the image provided.
d. Draw the regression line on the scatter diagram using the yp points.e. Find y for x = 50 x 20 10 30 40 60 70 y 20 20 30 50 60 80

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