Complete the explanation, which proves the Chord-Chord Product Theorem. Glven: Chords AB and CD Intersect at point E. Prove: AE EB = CE ED (Hint: Draw AC and BD.) D. v, then AC and BD can be drawn. Since through any two points there (select) ZACD (select) v because they intercept the same arc. ZCEA (select) v by the Vertical Angles Theorem. Therefore, AAEC and (select) v are similar by the AA Similarity Theorem. Corresponding СЕ AE sides are proportional, so ED (select) v CE AE (EB ED)= ED · (EB ED), or AE EB = (select) v (select) v
Angles in Circles
Angles within a circle are feasible to create with the help of different properties of the circle such as radii, tangents, and chords. The radius is the distance from the center of the circle to the circumference of the circle. A tangent is a line made perpendicular to the radius through its endpoint placed on the circle as well as the line drawn at right angles to a tangent across the point of contact when the circle passes through the center of the circle. The chord is a line segment with its endpoints on the circle. A secant line or secant is the infinite extension of the chord.
Arcs in Circles
A circular arc is the arc of a circle formed by two distinct points. It is a section or segment of the circumference of a circle. A straight line passing through the center connecting the two distinct ends of the arc is termed a semi-circular arc.
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