Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
Which of the following is an inscribed

Transcribed Image Text:**Question:**
Which of the following is an inscribed angle?
**Diagram Explanation:**
The image depicts a circle with labeled points P, Q, R, and C.
- **Points P, Q, and R** are located on the circumference of the circle.
- **Point C** is located inside the circle.
There are three line segments:
1. **Segment PQ** (in blue) connects points P and Q on the circle.
2. **Segment PR** (in purple) connects points P and R on the circle.
3. **Segment PC** (in pink) connects point P on the circle with point C inside the circle.
The inscribed angle formed is ∠PQR since it is created by two chords, PQ and PR, that meet at point R on the circle's circumference.
Whereas ∠PCR cannot be an inscribed angle because point C is not on the circle's circumference.
![## General Equation of a Circle
The general equation for a circle is given by:
\[
(x-a)^2 + (y-b)^2 = r^2
\]
Where:
- \((a, b)\) is the center of the circle.
- \(r\) is the radius of the circle.
### Examples:
1) **Equation:** \(x^2 + y^2 = 121\)
- Rearrange: \((x-0)^2 + (y-0)^2 = 11^2\)
- **Center:** \((0, 0)\)
- **Radius:** 11
2) **Equation:** \((x-2)^2 + y^2 = 64\)
- Rearrange: \((x-2)^2 + (y-0)^2 = 8^2\)
- **Center:** \((2, 0)\)
- **Radius:** 8
3) **Equation:** \(\left(x+\frac{3}{2}\right)^2 + \left(y+\frac{5}{8}\right)^2 = 36\)
- Rearrange: \(\left(x - \left(-\frac{3}{2}\right)\right)^2 + \left(y - \left(-\frac{5}{8}\right)\right)^2 = 6^2\)
- **Center:** \(\left(-\frac{3}{2}, -\frac{5}{8}\right)\)
- **Radius:** 6
4) **Equation:** \((x-1)^2 + (y+7)^2 = 9\)
- Rearrange: \((x-1)^2 + (y-(-7))^2 = 3^2\)
- **Center:** \((1, -7)\)
- **Radius:** 3
5) **Equation:** \((x+8)^2 + (y-3)^2 = 7\)
- Rearrange: \((x-(-8))^2 + (y-3)^2 = (\sqrt{7})^2\)
- **Center:** \((-8, 3)\)
- **Radius:** \(\sqrt{7}\)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7b987535-d752-4950-9b3b-7bc7d6cfe3bd%2F40360cb2-a58c-4a82-a1fa-23546c9b1849%2F1fjqaeq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## General Equation of a Circle
The general equation for a circle is given by:
\[
(x-a)^2 + (y-b)^2 = r^2
\]
Where:
- \((a, b)\) is the center of the circle.
- \(r\) is the radius of the circle.
### Examples:
1) **Equation:** \(x^2 + y^2 = 121\)
- Rearrange: \((x-0)^2 + (y-0)^2 = 11^2\)
- **Center:** \((0, 0)\)
- **Radius:** 11
2) **Equation:** \((x-2)^2 + y^2 = 64\)
- Rearrange: \((x-2)^2 + (y-0)^2 = 8^2\)
- **Center:** \((2, 0)\)
- **Radius:** 8
3) **Equation:** \(\left(x+\frac{3}{2}\right)^2 + \left(y+\frac{5}{8}\right)^2 = 36\)
- Rearrange: \(\left(x - \left(-\frac{3}{2}\right)\right)^2 + \left(y - \left(-\frac{5}{8}\right)\right)^2 = 6^2\)
- **Center:** \(\left(-\frac{3}{2}, -\frac{5}{8}\right)\)
- **Radius:** 6
4) **Equation:** \((x-1)^2 + (y+7)^2 = 9\)
- Rearrange: \((x-1)^2 + (y-(-7))^2 = 3^2\)
- **Center:** \((1, -7)\)
- **Radius:** 3
5) **Equation:** \((x+8)^2 + (y-3)^2 = 7\)
- Rearrange: \((x-(-8))^2 + (y-3)^2 = (\sqrt{7})^2\)
- **Center:** \((-8, 3)\)
- **Radius:** \(\sqrt{7}\)
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