Complete the design of the amplifier shown so that IDS =1.23mA and Av = Vo/Vi = -3 1. Rsl = ohm 2. Rs2 = ohm +20V 8KO C2 Vo(t) C1 H IDSS = 2mA Vp = = -2V 4KO Vi(t) 50KO Rs1 Rs2 C3
Complete the design of the amplifier shown so that IDS =1.23mA and Av = Vo/Vi = -3 1. Rsl = ohm 2. Rs2 = ohm +20V 8KO C2 Vo(t) C1 H IDSS = 2mA Vp = = -2V 4KO Vi(t) 50KO Rs1 Rs2 C3
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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![Complete the design of the amplifier shown so that IDS =1.23mA and Av = Vo/Vi = -3
1. Rs1 =
ohm
2. Rs2 =
ohm
I+20V
8KO
C2
Vo(t)
C1
Ipss
Vp
= 2mA
= -2V 4KQ
Vilt)
50KO
Rs1
C3
Rs2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8eed163c-0109-45bb-bdff-e50d03065ca6%2F013481b2-4d24-48db-a8be-1f863dad6771%2F35eyn4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Complete the design of the amplifier shown so that IDS =1.23mA and Av = Vo/Vi = -3
1. Rs1 =
ohm
2. Rs2 =
ohm
I+20V
8KO
C2
Vo(t)
C1
Ipss
Vp
= 2mA
= -2V 4KQ
Vilt)
50KO
Rs1
C3
Rs2
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