Complete and balance the following skeletal reaction using the half reaction method. (This question is broken into steps and all the following questions are for balancing this one reaction).  Mn2+   +     BiO3–    →    MnO4– +     Bi3+   [acidic] Now balance the half reactions separately. Fist balance the non-oxygen, non-hydrogen elements for the half reaction:    Mn2+      →    MnO4–      and since there is one Mn on each side that is done. Second balance the oxygen by adding water. How many water are added and to which side? a. None of these b. 8 water to the reactant side c. 3 water to the reactant side d. 3 water to the product side e. 4 water to the reactant side f. 4 water to the product side g. 8 water to the product side   Continuation of previous problem. Third, balance hydrogen by adding H+ ions. How many H+ are added and to which side of the Mn2+ half reaction? Select one: a. 3 H+ to the product side b. 4 H+ to the reactant side c. 8 H+ to the reactant side d. 4 H+ to the product side e. None of these f. 3 H+ to the reactant side g. 8 H+ to the product side   Continuation of previous problem. Fourth, balance charge by adding electrons. How many electrons are added and to which side of the Mn2+ half reaction? Select one: a. 5 electrons to the reactant side b. 7 electrons to the product side c. 4 electrons to the product side d. 3 electrons to the reactant side e. 4 electrons to the reactant side f. 7 electrons to the reactant side g. None of these h. 5 electrons to the product side i. 3 electrons to the product side     Now we want to balance the other half reaction:    BiO3–    →      Bi3+    There is one Bi on each side, so we go to the 2nd step, how many waters are added and to which side? Select one: a. 8 water to the product side b. 3 water to the reactant side c. 4 water to the reactant side d. None of these e. 4 water to the product side f. 8 water to the reactant side g. 3 water to the product side   Continuation of previous problem. Third, balance hydrogen by adding H+ ions. How many H+ are added and to which side of the BiO3– half reaction? Select one: a. 4 H+ to the reactant side b. 4 H+ to the product side c. 3 H+ to the reactant side d. 6 H+ to the product side e. 6 H+ to the reactant side f. None of these g. 3 H+ to the product side   Continuation of previous problem. Fourth, balance charge by adding electrons. How many electrons are added and to which side of the BiO3– half reaction? Select one: a. 2 electrons to the reactant side b. 4 electrons to the reactant side c. 5 electrons to the reactant side d. 7 electrons to the product side e. 2 electrons to the product side f. 4 electrons to the product side g. 3 electrons to the reactant side h. None of these i. 5 electrons to the product side   Now you have balanced each half reaction. Before adding the two half reactions, do you need to multiply ether half reaction by something to get to the same number of electrons gained and lost? If so, how many electrons do you need in each half reaction? Select one: a. 1 electron b. None of these c. 10 electrons d. 5 electrons e. 6 electrons f. 4 electrons g. 2 electrons h. 8 electrons i. 9 electrons j. 3 electrons k. 7 electrons   Now add the two half reactions and eliminate the electrons.  Write that answer here

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 Complete and balance the following skeletal reaction using the half reaction method. (This question is broken into steps and all the following questions are for balancing this one reaction).
 Mn2+   +     BiO3–    →    MnO4 +     Bi3+   [acidic]
Now balance the half reactions separately. Fist balance the non-oxygen, non-hydrogen elements for the half reaction:
   Mn2+      →    MnO4     
and since there is one Mn on each side that is done.
Second balance the oxygen by adding water. How many water are added and to which side?

a. None of these
b. 8 water to the reactant side
c. 3 water to the reactant side
d. 3 water to the product side
e. 4 water to the reactant side
f. 4 water to the product side
g. 8 water to the product side
 
Continuation of previous problem. Third, balance hydrogen by adding H+ ions. How many H+ are added and to which side of the Mn2+ half reaction?
Select one:
a. 3 H+ to the product side
b. 4 H+ to the reactant side
c. 8 H+ to the reactant side
d. 4 H+ to the product side
e. None of these
f. 3 H+ to the reactant side
g. 8 H+ to the product side
 
Continuation of previous problem. Fourth, balance charge by adding electrons. How many electrons are added and to which side of the Mn2+ half reaction?
Select one:
a. 5 electrons to the reactant side
b. 7 electrons to the product side
c. 4 electrons to the product side
d. 3 electrons to the reactant side
e. 4 electrons to the reactant side
f. 7 electrons to the reactant side
g. None of these
h. 5 electrons to the product side
i. 3 electrons to the product side
 
 
Now we want to balance the other half reaction:
   BiO3–    →      Bi3+   
There is one Bi on each side, so we go to the 2nd step, how many waters are added and to which side?
Select one:
a. 8 water to the product side
b. 3 water to the reactant side
c. 4 water to the reactant side
d. None of these
e. 4 water to the product side
f. 8 water to the reactant side
g. 3 water to the product side
 
Continuation of previous problem. Third, balance hydrogen by adding H+ ions. How many H+ are added and to which side of the BiO3 half reaction?
Select one:
a. 4 H+ to the reactant side
b. 4 H+ to the product side
c. 3 H+ to the reactant side
d. 6 H+ to the product side
e. 6 H+ to the reactant side
f. None of these
g. 3 H+ to the product side
 
Continuation of previous problem. Fourth, balance charge by adding electrons. How many electrons are added and to which side of the BiO3 half reaction?
Select one:
a. 2 electrons to the reactant side
b. 4 electrons to the reactant side
c. 5 electrons to the reactant side
d. 7 electrons to the product side
e. 2 electrons to the product side
f. 4 electrons to the product side
g. 3 electrons to the reactant side
h. None of these
i. 5 electrons to the product side
 
Now you have balanced each half reaction. Before adding the two half reactions, do you need to multiply ether half reaction by something to get to the same number of electrons gained and lost? If so, how many electrons do you need in each half reaction?
Select one:
a. 1 electron
b. None of these
c. 10 electrons
d. 5 electrons
e. 6 electrons
f. 4 electrons
g. 2 electrons
h. 8 electrons
i. 9 electrons
j. 3 electrons
k. 7 electrons
 
Now add the two half reactions and eliminate the electrons.  Write that answer here.
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