Compile and execute the following code with a GCC compiler and write down the output of the code. Explain where those three printed values come from. #include int main() { } unsigned long address = 0x6F477D30; char buf[4]; printf("%d\n", sizeof (address)); buf [0] = address & 0x000000ff; buf [1] = (address & 0x0000ff00) >> 8; printf("0xx\n", buf[0]); buf[1]); printf("0x8x\n", Based on what you understand from #13, what code should be used to make the fourth byte of buf be the high byte of address (6F)? a. buf[3] = address & 0xff000000; b. buf [3] c. buf [3] = d. buf [4] = = (address & 0x00ff0000) >> 16; (address & 0xff000000) >> 24; (address & 0xff000000) >> 32; 4
Compile and execute the following code with a GCC compiler and write down the output of the code. Explain where those three printed values come from. #include int main() { } unsigned long address = 0x6F477D30; char buf[4]; printf("%d\n", sizeof (address)); buf [0] = address & 0x000000ff; buf [1] = (address & 0x0000ff00) >> 8; printf("0xx\n", buf[0]); buf[1]); printf("0x8x\n", Based on what you understand from #13, what code should be used to make the fourth byte of buf be the high byte of address (6F)? a. buf[3] = address & 0xff000000; b. buf [3] c. buf [3] = d. buf [4] = = (address & 0x00ff0000) >> 16; (address & 0xff000000) >> 24; (address & 0xff000000) >> 32; 4
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
Related questions
Question
use 32 bit machinr only
![Compile and execute the following code with a GCC compiler and write down the output of the
code. Explain where those three printed values come from.
#include<stdio.h>
int main() {
}
unsigned long address = 0x6F477D30;
char buf [4];
printf("%d\n", sizeof (address));
buf [0] = address & 0x000000ff;
buf [1] = (address & 0x0000ff00) >> 8;
printf("0xx\n", buf[0]);
printf("0x%x\n", buf[1]);
Based on what you understand from #13, what code should be used to make the fourth byte of
buf be the high byte of address (6F)?
a. buf [3] = address & 0xff000000;
b. buf [3] =
c. buf [3] =
d. buf[4] =
(address & 0x00ff0000) >> 16;
(address & 0xff000000) >> 24;
(address & 0xff000000) >> 32;](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6553e9a2-ab6c-4fa4-8011-219f0a936acb%2F14dae12b-6e93-4662-922a-4a5e1fe1f160%2Fuvd7yt5_processed.png&w=3840&q=75)
Transcribed Image Text:Compile and execute the following code with a GCC compiler and write down the output of the
code. Explain where those three printed values come from.
#include<stdio.h>
int main() {
}
unsigned long address = 0x6F477D30;
char buf [4];
printf("%d\n", sizeof (address));
buf [0] = address & 0x000000ff;
buf [1] = (address & 0x0000ff00) >> 8;
printf("0xx\n", buf[0]);
printf("0x%x\n", buf[1]);
Based on what you understand from #13, what code should be used to make the fourth byte of
buf be the high byte of address (6F)?
a. buf [3] = address & 0xff000000;
b. buf [3] =
c. buf [3] =
d. buf[4] =
(address & 0x00ff0000) >> 16;
(address & 0xff000000) >> 24;
(address & 0xff000000) >> 32;
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