company claims that the mean monthly reside oWatt-hours (kWh). You want to test this clain onthly consumption of 900 kWh. Assume the e claim? Complete parts (a) through (e). A. The rejection regions are z< -2.33 and VB. The rejection region is z>2.33. The rainction rosion is 72.33
company claims that the mean monthly reside oWatt-hours (kWh). You want to test this clain onthly consumption of 900 kWh. Assume the e claim? Complete parts (a) through (e). A. The rejection regions are z< -2.33 and VB. The rejection region is z>2.33. The rainction rosion is 72.33
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
Identify the standardized test statistic use technology.
decide whether to reject or fail the null hypothesis and interpret the decision in the context of Original claim
![A company claims that the mean monthly residential electricity consumption in a certain region is more than 880
kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean
monthly consumption of 900 kWh. Assume the population standard deviation is 126 kWh. At a= 0.01, can you support
the claim? Complete parts (a) through (e).
A. The rejection regions are z< -2.33 and z>2.33.
B. The rejection region is z>2.33.
C. The rejection region is z < 2.33.
(c) Find the standardized test statistic. Use technology.
The standardized test statistic is z =
(Round to two decimal places as needed.)
B
Hill](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6fde1cf5-26e3-4bb2-84a4-1392c432c211%2F5b4d6015-417a-402f-b846-b6e0f0263635%2Fjvormlq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A company claims that the mean monthly residential electricity consumption in a certain region is more than 880
kilowatt-hours (kWh). You want to test this claim. You find that a random sample of 69 residential customers has a mean
monthly consumption of 900 kWh. Assume the population standard deviation is 126 kWh. At a= 0.01, can you support
the claim? Complete parts (a) through (e).
A. The rejection regions are z< -2.33 and z>2.33.
B. The rejection region is z>2.33.
C. The rejection region is z < 2.33.
(c) Find the standardized test statistic. Use technology.
The standardized test statistic is z =
(Round to two decimal places as needed.)
B
Hill
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