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Common aluminum foil for household use is nearly pure aluminum. A box of this product at a local supermarket is advertised as giving 75 A'of material (in a roll 304 mm wide by 22.8 m long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the roll. Given: Density of Aluminum: p= 2.7 Mg/m Molar mass of Aluminum: MAI= 26.98 g/mol Avogadro's Number: AN =0.6203 (10)ª

Common aluminum foil for household use is nearly pure aluminum. A box of this product at a local supermarket is advertised as giving 75 A'of material (in a roll 304 mm wide by 22.8 m long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the roll. Given: Density of Aluminum: p= 2.7 Mg/m Molar mass of Aluminum: MAI= 26.98 g/mol Avogadro's Number: AN =0.6203 (10)ª

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Common aluminum foil for household use is nearly pure aluminum. A box of this product at a local supermarket is advertised as giving 75 ft°of material (in a roll 304 mm wide by 22.8 m long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the roll. Given: Density of Aluminum: p= 2.7 Mg/m³ Molar mass of Aluminum: MAI= 26.98 g/mol Avogadro's Number: AN = 0.6203 (10)²ª
Transcribed Image Text:Common aluminum foil for household use is nearly pure aluminum. A box of this product at a local supermarket is advertised as giving 75 ft°of material (in a roll 304 mm wide by 22.8 m long). If the foil is 0.5 mil (12.7 µm) thick, calculate the number of atoms of aluminum in the roll. Given: Density of Aluminum: p= 2.7 Mg/m³ Molar mass of Aluminum: MAI= 26.98 g/mol Avogadro's Number: AN = 0.6203 (10)²ª
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