Combustion of glucose (C₂H₂O₂) is the main source of energy for animal cells:C₂H₁0()+60₂(g) 6CO₂(g) + 6H₂O()AG,(37 "C)--2872. kJOne of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation ofone peptide bond, joining one amino acid to another, is 21 kJ/mol.Suppose some cells are assembling a certain protein made of 82 amino acids. (Note that the number of peptide bonds in the protein will be one less than thenumber of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 800. umol of this protein.Round your answer to 2 significant digits.08D.PX1426

Gibbs free energy of the reaction = -2872 kJGibbs free energy of the formation of one peptide bond =…

Combustion of glucose (CHO) is the main source of energy for animal cells: C₂H₂O₂()+60₂(e) 6C0₂(g) + 6H₂0 (1) AG,..(37 °C)--2872. kJ One of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation of one peptide bond, joining one amino acid to another, is 21 kmol Suppose some cells are assembling a certain protein made of 82 amino acids. (Note that the number of peptide bonds in the protein will number of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 800 ml of this protein. Round your answer to 2 significant digts. 0 O.P e one less than the

Combustion of glucose (CHO) is the main source of energy for animal cells: C₂H₂O₂()+60₂(e) 6C0₂(g) + 6H₂0 (1) AG,..(37 °C)--2872. kJ One of the most important uses to which this energy is put is the assembly of proteins out of amino acid building blocks. The Gibbs free energy of formation of one peptide bond, joining one amino acid to another, is 21 kmol Suppose some cells are assembling a certain protein made of 82 amino acids. (Note that the number of peptide bonds in the protein will number of amino acids.) Calculate the minimum mass of glucose that must be burned to assemble 800 ml of this protein. Round your answer to 2 significant digts. 0 O.P e one less than the

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Given the solubility of ferrihydrite (Fe(OH)3) and goethite (FeOOH), with dissolution reactions shown below: [1] Fe(OH)3 3 H+ à Fe3+ + 3 H2O Ksp = 8.4 x 10^4 ∆ Gr0 = -28 KJ/mol Solubility of Fe(OH3) = 7.468 [2] FeOOH + 3 H+ à Fe3+ + 2 H2O Ksp = 8.8 x 10^-2 ∆ Gr0 = 6 KJ/mol Solubility of FeOOH = 0.353 QUESTION: [A] How much Fe3+ from ferrihydrite would dissolve at pH 2 ? [B] How much Fe3+ from ferrihydrite would dissolve at pH 7 ? [C] How much Fe3+ from goethite would dissolve at pH 2 ? [D] How much Fe3+ from goethite would dissolve at pH 7 ?
Use heats of formation data bellow to calculate AH° for the reaction: Ca(OH)2 (s) + H2SO 4 () → CaSO4 (s) +2 H20 (1). AH°;(Ca(OH), (s)) = -986.59 kJ/mol AH°;(H2O (1)) = -285.9 kJ/mol AH°;(H2SO4 (1) = -811.32 kJ/mol AH°;(CaSO4 (s)) = -1432.7 kJ/mol AH° = kJ eTextbook and Media Hint Type'here.to search hp 12 47 &
Hi!!! I just need help with question 9, please!!
34. Calculate the standard enthalpy change (AH) at 298 K for the reaction of X&Y18 with O2. 2 XBY18+21 O2→8 XO +8 XO2 +18 Y,0 Reaction AH at 298 K 2 XgY18+25 O2 16 XO, + 18 Y O -11020 kJ 2 XO +O2 XO -566.0 kJ 210454 kJ 18756 J 0 13284 J D 1E5
(a) Fe(OH);(s) – FeO(OH)(s) + H;0() AH =-24.3 kJ/mol AH - 35.6 kJ/mol 298 (b) Fe;O(s) + 3H:O(() 2Fe(OH)3(s) (c) 2FEO(OH)(s) Fe,Os(s) + H20() !! 298 AG98 for process (a) is -31.3 kJ / mol and AG for process (c) is 1.7 kJ /mol. Calculate G2 O A) 179.0 kJ/mol O B)-372.6 kJ/mol OC) -490.6 kJ/mol OD) 231.2 kJ/mol Q 5: for FeO(OH)(s)! 298
oxygen Photosynthesis in plants converts carbon dioxide and water into glucose (C,H,O) and according to the equation below. 6CO₂(g) + 6H₂O() - CH₂O() + 60₂(g) Substance CO(g) H₂O(1) C₂H₁₂O(s) O(g) AHi(kJ/mol) -393.5 -285.8 -1273.3 0 SᵒJ/mol K) 213.6 69.9 209.2 205.0 Calculate the AH, AS, and AG. Is the reaction spontaneous at standard conditions?
18. From the following reacțions and thermal data at 25°C 3 2 Fe(s) +O:(g) 2 Fe,O:(s) ΔΗ - 196,500 cal %3D 1 2 FeO(s) + ; 0:(g) - Fe2O:(s) AH° = -67,900 cal Fe(s) + 2 H* (a = 1) = Fe++ (a = 1) + H2(g) AH° = -21,000 cal %3D %3D 1 H:(g) H* (a = 1) AHº = 0 cal %3D Hig) +0:(g) = H;0(1) AH° = -68,320 cal %3D calculate AH° of the reaction: FeO(s) + 2 H+ (a = 1) = H;0(1) + Fe++ (a = 1) %3D
Calculate the AG in kJ of the following reaction: NO₂ (g) + SO₂ (g) --> NO (g) + SO3 (8) Given the following data: AGO (NO₂) = 50.84 kJ/mol AGO (SO₂) = 81.16 kJ/mol AGO (NO) = -304.30 kJ/mol AGO (SO3) = -377.04 kJ/mol Do not put a unit in your answer. Report your answer with 1 place past the decimal point. Do not use scientific notation.
ellus_engine.html?ClassID=1087757335# Calculate the standard reaction enthalpy for the reaction between NO and O3. NO(g) + O3(g) NO2(g) + O2(g) Compound AH°; (kJ/mol) NO(g) 90. AHxn = [ ? ] kJ %3D 0,(8) NO,(g) 143 34 Enter either a + or - sign and the magnitude. Enter
(1) C(s) + O2(g) CO2(8) AH, = -393.5 kJ AH = -283.0 kJ Using these data, calculate the enthalpy for the combustion of C to CO: (2) CO(g) + 02(8) CO2(8) - %3D (3) C(s) + 02(8) CO(g) AH3 = ? 24 - O A) 403.5 O B) 676.5 403.5 O D) 110.5 O E) -110.5
Consider the following problem. How much energy is evolved during the formation of 197 g of Fe, according to the reaction below? Fe203(s) + 2 Al(s) - Al203(s) + 2 Fe(s) AH°rxn = -852 kJ 21. How do you find the correct answer to the problem question? ODH(rxn of 197 g of Fe) = ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe in equation) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next. O DH(rxn of 197 g of Fe) = ratio of (2 mol of Fe in equation / #mol from 197g of Fe in reaction) x DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next. DH(rxn of 197 g of Fe) = ratio of (#mol from 197g of Fe in reaction / 2 mol of Fe in equation) / DH(rxn of 2 mol of Fe). #mol from 197 g of is not known and should be determined next.
Sucrose, C12 Hzm011, is common table sugar. The enthalpy change at 25°C and 1 atm for the complete burning of 3 mol of sucrose in oxygen to give CO:(9) and H3O(1) is - 1.692 x 10' kJ. From this and from data given below: AH; (H2O(1)) =-285.8 kJ/mol AH(CO2(9) = -393.5 kJ/mol AH (02(9)) = 0 kJ/mol Calculate the standard enthalpy of formation of sucrose. AH; - k]/mol