Combined test scores were normally distributed with mean 1494 and standard deviation 347. Find the combined scores that correspond to these percentiles. a) 10th percentile b) 75th percentile c) 80th percentile Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a) The combined scores that correspond to 10th percentile is about (Round to the nearest integer as needed.) b) The combined scores that correspond to 75th percentile is about (Round to the nearest integer as needed.) c) The combined scores that correspond to 80th percentile is about (Round to the nearest integer as needed.)
Combined test scores were normally distributed with mean 1494 and standard deviation 347. Find the combined scores that correspond to these percentiles. a) 10th percentile b) 75th percentile c) 80th percentile Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. a) The combined scores that correspond to 10th percentile is about (Round to the nearest integer as needed.) b) The combined scores that correspond to 75th percentile is about (Round to the nearest integer as needed.) c) The combined scores that correspond to 80th percentile is about (Round to the nearest integer as needed.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:Entries in the table represent area under the curve between z = 0 and a positive value of z. Because of the symmetry of the
curve, area under the curve between 2 = 0 and a negative value of z are found in a similar manner.
0.02
0.03
0.04
Area Probability
= P(0 ≤ x ≤ 2)
0.1
= 1 √/2²²
0.00 0.01
0.05
0.06 0.07 0.08 0.09
0.0 .0000 .0040 .0080 .0120 .0160 .0199 .0239 0279 .0319 .0359
.0438 .0478 .0517 .0557 .0596 .0636 .0675 0714 .0753
.0832 .0871 .0910 .0948 .0987 .1026 .1064 .1103 .1141
1217 .1255 .1293 .1331 .1368 .1406 .1443 .1480 1517
.1591 .1628 .1664 .1700 .1736 .1772 .1808 .1844 .1879
=
ex²/2 dx
.0398
0.2 .0793
0.3 .1179
.1554
с
0.4
.2224
.2549
.2852
0.5 .1915 .1950 .1985 .2019 .2054 2088 .2123 .2157 .2190
0.6 .2257 .2291 .2324 .2357 .2389 .2422 .2454 .2486 .2517
0.7 .2580 .2611 .2642 .2673 .2704 .2734 .2764 2794 .2823
.2910 2939 .2967 .2995 .3023 .3051 .3078 .3106 .3133
.3186 .3212 .3238 .3264 .3289 .3315 .3340 .3365
0 z
0.8 .2881
0.9 .3159
.3389
1.0
1.1
.3413 .3438 .3461 .3485 .3508 .3531 3554 .3577 .3599
.3643 .3665 .3686 3708 .3729 .3749 .3770 .3790 3810
1.2 .3849 .3869 .3888 .3907 .3925 .3944 .3962 .3980 .3997
1.3. .4032 .4049 .4066 .4082 .4099 .4115 .4131 .4147 .4162
1.4 .4192 .4207 .4222 .4236 .4251 .4265 .4279 .4292 .4306 .4319
.3621
.3830
.4015
.4177
M88 888888=223
Q
Entries in the table represent area under the curve between z = 0 and a positive value of z. Because of the symmetry of the
curve, area under the curve between z = 0 and a negative value of z are found in a similar manner.
Area Probability
= P(0 ≤ x ≤ z)
-²/2 dx
= 5 +√7/20²0
.4545
z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09
1.5 .4332 .4345 .4357
.4370
.4382 .4394 .4406 .4418 .4429 .4441
1.6 4452 .4463 ,4474 .4484 .4495
.4515
.4505
.4525 .4535
1.7 .4554 .4564 .4573 .4582 4591 4599 .4608 .4616 4625 .4633
1.8 .4641 .4649 .4656 .4664 .4671 .4678 .4686 .4693 .4699
1.9 .4713 .4719 4726 .4732 .4738 .4744 .4750 .4756 .4761
2πT
.4706
.4767
2.0 .4772 .4778 .4783 .4788 .4793 .4798 .4803 .4808 .4812 .4817
2.1 .4821 .4826 .4830 .4834 .4838 .4842 .4846 .4850 .4854 .4857
2.2 .4861 .4864 .4868 .4871 .4875 .4878 .4881 .4884 .4887 .4890
2.3 .4893 .4896 .4898 .4901 .4904 .4906 .4909 .4911 .4913 .4916
2.4 .4918 .4920 4922 .4925 .4927 .4929 4931 .4932 .4934 .4936
0z
2.5 .4938 .4940 .4941 .4943 .4945 .4946 .4948 .4949
2.6 .4953 .4955 .4956 .4957 .4959 .4960 .4961 .4962
2.7 .4965 .4966 .4967 .4968 .4969 .4970 .4971 .4972
2.8 .4974 .4975 .4976 .4977 .4977 .4978 .4979 .4979
2.9 .4981 .4982 .4982 .4983 .4984 .4984 .4985 .4985
3.0 .4987 .4987 .4987 .4988 .4988 .4989 .4989 .4989
.4951 .4952
.4963 .4964
.4973 .4974
.4980
.4986
.4990
.4981
.4986
.4990
Transcribed Image Text:Combined test scores were normally distributed with mean 1494 and standard deviation 347. Find the combined scores that correspond to these percentiles.
a) 10th percentile b) 75th percentile c) 80th percentile
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
a) The combined scores that correspond to 10th percentile is about
(Round to the nearest integer as needed.)
b) The combined scores that correspond to 75th percentile is about
(Round to the nearest integer as needed.)
c) The combined scores that correspond to 80th percentile is about
(Round to the nearest integer as needed.)
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