Combined Spectra 14.46 Identify the C3 H5Br isomers on the basis of the following information: (a) Isomer A has the 'H NMR spectrum shown in 4 Figure 14.49. (b) Isomer B has three peaks in its 13C NMR spectrum: 8 32.6 (CH2); 118.8 (CH2 ); and 134.2 (CH). (c) Isomer C has two peaks in its 13C NMR spectrum: ô 12.0 (CH2) and 16.8 (CH). The peak at lower field is only half as intense as the one at higher field. 10 9 8 7 4 3 2 1 Chemical shift (8, ppm)

Combined Spectra 14.46 Identify the C3 H5Br isomers on the basis of the following information: (a) Isomer A has the 'H NMR spectrum shown in 4 Figure 14.49. (b) Isomer B has three peaks in its 13C NMR spectrum: 8 32.6 (CH2); 118.8 (CH2 ); and 134.2 (CH). (c) Isomer C has two peaks in its 13C NMR spectrum: ô 12.0 (CH2) and 16.8 (CH). The peak at lower field is only half as intense as the one at higher field. 10 9 8 7 4 3 2 1 Chemical shift (8, ppm)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mass Spectrometry

This process is an instrumental method in which a sample is changed to fast moving positive ions by electron bombardment. The charged particles vary due to their different mass to charge ratio and are estimated with the help of this difference. It is also called mass spectroscopy.

Question

Combined Spectra
14.46
Identify the C3 H5 Br isomers on the basis of the following information:
(a) Isomer A has the 'H NMR spectrum shown in 4 Figure 14.49.
(b) Isomer B has three peaks in its 13C NMR spectrum: 8 32.6 (CH2 ); 118.8 (CH2 ); and 134.2 (CH).
(c) Isomer C has two peaks in its 1°C NMR spectrum: 8 12.0 (CH2) and 16.8 (CH). The peak at lower
field is only half as intense as the one at higher field.
10
9.
8
7
6.
5
4
3
2
1
Chemical shift (8, ppm)

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Cyclohex-2-enone has two protons on its carbon–carbon double bond (labeled Ha and Hb) and two protons on the carbon adjacent to the double bond (labeled Hc). (a) If Jab = 11 Hz and Jbc = 4 Hz, sketch the splitting pattern observed for each proton on the sp2 hybridized carbons. (b) Despite the fact that Ha is located adjacent to an electron-withdrawing C = O, its absorption occurs upfield from the signal due to Hb (6.0 vs. 7.0 ppm). Offer an explanation.