Combination of Variables. A boundary layer expert uses a combination of variables n= ay/x¹/2 together with = bx¹/2 f(n), where a and b are constants. It is found that for flow of air near a flat plate f(n) = 0.3n². If a = 1000 and b = 0.001, compute (a) the shear stress at the plate in air at x = 50cm; (b) the air velocity at y = 0.1mm and x = 50cm; (c) the total drag force, FD, on a square plate L = W = 4m. Ans OM: (a) t: 10-2 Pa; (b) u: 10-2 m/s; (c) FD:10-¹ N
Combination of Variables. A boundary layer expert uses a combination of variables n= ay/x¹/2 together with = bx¹/2 f(n), where a and b are constants. It is found that for flow of air near a flat plate f(n) = 0.3n². If a = 1000 and b = 0.001, compute (a) the shear stress at the plate in air at x = 50cm; (b) the air velocity at y = 0.1mm and x = 50cm; (c) the total drag force, FD, on a square plate L = W = 4m. Ans OM: (a) t: 10-2 Pa; (b) u: 10-2 m/s; (c) FD:10-¹ N
Elements Of Electromagnetics
7th Edition
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ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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![Assume Patm = 10^5, Pa = 14.7 psi; pwater ~ 1000 kg/m3; pair ~ 1.2 kg/m3; μwater ~ 10^-3 N•s/m2; pair ~ 2 x 10^-5 N•s/m2; Vwater ~ 10^-6 m2 /s; Vair
~ 1.67 x 10^-5 m2 /s ; g = 9.8 m/s^2 .; 1 m/s = 2.24 mph; 1lbf = 4.45 N; 1 m^3 = 264 gallons
Changing variables, the IBL eq'n 9.21 can be written as: TW = pU^2 (d8/dx) [S(u/U)(1-u/U)dn] where ny/6, with integral limits 0 to 1. Assuming profiles of the
form u/U = f(n) then the integral value is a pure number. Again, for turbulent IBL we set TW = 0.0233 pU^2 [v/(US)]^(1/4) on LHS
Combination of Variables. A boundary layer expert uses a combination of variables n = ay/x1¹/2 together with
y = bx¹/² f(n), where a and b are constants. It is found that for flow of air near a flat plate ƒ(n) = 0.3ŋ². If a = 1000
and b = 0.001, compute (a) the shear stress at the plate in air at x = 50cm; (b) the air velocity at y = 0.1mm and x = = 50cm;
(c) the total drag force, Fò, on a square plate L = W = 4m. Ans OM: (a) t: 10-² Pa; (b) u: 10-² m/s; (c) FD:10-¹ N](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff46cd712-1d53-471c-8e4d-5e78c3c80932%2F32b45baf-e398-41ff-a453-1e3e9c5f05ea%2Fnpcpkmm_processed.png&w=3840&q=75)
Transcribed Image Text:Assume Patm = 10^5, Pa = 14.7 psi; pwater ~ 1000 kg/m3; pair ~ 1.2 kg/m3; μwater ~ 10^-3 N•s/m2; pair ~ 2 x 10^-5 N•s/m2; Vwater ~ 10^-6 m2 /s; Vair
~ 1.67 x 10^-5 m2 /s ; g = 9.8 m/s^2 .; 1 m/s = 2.24 mph; 1lbf = 4.45 N; 1 m^3 = 264 gallons
Changing variables, the IBL eq'n 9.21 can be written as: TW = pU^2 (d8/dx) [S(u/U)(1-u/U)dn] where ny/6, with integral limits 0 to 1. Assuming profiles of the
form u/U = f(n) then the integral value is a pure number. Again, for turbulent IBL we set TW = 0.0233 pU^2 [v/(US)]^(1/4) on LHS
Combination of Variables. A boundary layer expert uses a combination of variables n = ay/x1¹/2 together with
y = bx¹/² f(n), where a and b are constants. It is found that for flow of air near a flat plate ƒ(n) = 0.3ŋ². If a = 1000
and b = 0.001, compute (a) the shear stress at the plate in air at x = 50cm; (b) the air velocity at y = 0.1mm and x = = 50cm;
(c) the total drag force, Fò, on a square plate L = W = 4m. Ans OM: (a) t: 10-² Pa; (b) u: 10-² m/s; (c) FD:10-¹ N
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