Column E Mass of Single Bean (average from total mass of isotope/number of beans from that type)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter3: Stoichiometry
Section: Chapter Questions
Problem 40E: An element X bas five major isotopes, which are listed below along with their abundances. What is...
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Please help with column E
Chem 105 Online
Data Table
Column A
Bean Isotope
(assign a
number or
name)
speckled
Black
white
Column B
Number of
Beans
69
112
21
Column C
Total Mass in
Grams of
isotope
(mass of all
beans of this
type)
21.59
22.86
28.08
Calculations
1. What is the total mass of all the beans?
72.589
2. What is the total quantity of all the beans?
202
Column D
Abundance
(number of
beans/total
number beans)
3. Take # 1 and divide by #2. Include units.
.36g/bean
.34
. 10
Average Atomic Mass of Beanium (Total of the last column):
ما5.
Column E
Mass of Single
Bean (average
from total mass of
isotope/number of
beans from that
type)
Column F
Weighted Mass
(take abundance
* mass single
bean)
4. What is the average atomic mass of your element, Beanium? (this is the sum of column F).
Include Units.
5. Compare and contrast #3 and #4. How are they different and how are they similar?
6. Take the sum of column E. From the sum, divide by 3 since there is 3 types of beans.
7. Why is the process in number 6 of the post lab not a viable one for finding the average atomic
mass of isotopes in nature? (hint, think about what it assumes the weights to be)
Transcribed Image Text:Chem 105 Online Data Table Column A Bean Isotope (assign a number or name) speckled Black white Column B Number of Beans 69 112 21 Column C Total Mass in Grams of isotope (mass of all beans of this type) 21.59 22.86 28.08 Calculations 1. What is the total mass of all the beans? 72.589 2. What is the total quantity of all the beans? 202 Column D Abundance (number of beans/total number beans) 3. Take # 1 and divide by #2. Include units. .36g/bean .34 . 10 Average Atomic Mass of Beanium (Total of the last column): ما5. Column E Mass of Single Bean (average from total mass of isotope/number of beans from that type) Column F Weighted Mass (take abundance * mass single bean) 4. What is the average atomic mass of your element, Beanium? (this is the sum of column F). Include Units. 5. Compare and contrast #3 and #4. How are they different and how are they similar? 6. Take the sum of column E. From the sum, divide by 3 since there is 3 types of beans. 7. Why is the process in number 6 of the post lab not a viable one for finding the average atomic mass of isotopes in nature? (hint, think about what it assumes the weights to be)
Expert Solution
Step 1

Given that,

Column A Column B Column C Column E
Beans isotope  Number of beans Total mass in grams of isotope  Mass of single bean
Speckled 68 21.59  
Black 112 22.86  
White 21 28.08  

We have to calculate the mass of the single bean.

 

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