Column axial loads:D = 502KNL= 369 kNE = 210 kNAt ultimate condition:Case 1: 1.2D + 1.6LCase 2: 1.2D + E +L1. Determine the required nominal beam shearstrength (MPa).2. Determine the required nominal punchingshear strength (MPa).3. Determine the minimum required nominalflexural strength (kN-m) of the footing. The footing shown withan overall dimension of3m x 4.5m x 0.8m isloaded with a 600KNdead load and 630kNlive load. The column is0.6m square. The pilesare 0.4m in diameterand are spaced at 1.0mon centers.U=1.2D+1.6L.

Given the length of the footing L=4.5 m width of the footing B=3.0 mdepth of the footing…

Answered: Column axial loads: D = 502KN L= 369 kN…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Design the slab reinforcement if the maximum positive moment is Mup= wul2/11 and the maximum negative moment is Mun= wul2/10. Given: Superimposed dead load = 4.76 kPa Live Load = 1.9 kPa Weight of slab = 3.45 kPa Length = 10.9 m Span = 3m
3rd: A simply supported 12-m span beam, 300-mm wide by 550-mm deep, is pre- stressed by straight tendons with Aps = 774 mm² located 70 mm from the bottom at an initial prestress of 1.10 GPa. What maximum service uniform live load can the beam support in addition to its own weight if allowable tensile stress in concrete 0.5 x square root of f'c is permitted. after 17% loss Write your answer in 2 decimal places only. Use fc = 30 MPa unit weight of concrete 24 kN/cu.m. Sign convention is (+) tension, (-) compression. Indicate the sign in your final answer.
5 A square footing 2.4 m x 0.35 m thick supports a 300 mm square column at its center. Column loads are service conditions: DL = 372 kN LL = 293 kN f’c = 21 MPa fy = 415 MPa Concrete cover to the centroid of steel reinforcement = 100 mm Calculate the maximum ultimate bending moment in the slab. Write your final answer as whole number with the unit of kN-m.
1. A rectangular beam section is 10 in. wide and has a structural depth of 13.5 in. Reinforcement consists of two No. 8 bars. Given that the strength normal weight concrete is 4000 psi and there is NO shear reinforcement in the section, determine the nominal shear capacity allowed by the ACI Code. (5 pt) (Hint: No web reinforcement, so Vc = 8λ¸^(pw)¹/³√fcbwd shall be used).
Design the one way slab using strength design method with the following data. Effective span=15 feet Fc=3000psi Fy=60000psi L.L=200 psf D.L=100 psf (Excluded self_wieght of slab)
A simply supported 1 way slab having span of 3 meters is to carry the load for DL = 5kpa and LL = 4.8Kpa. If the concrete f'c = 28Mpa and rebar to be used is 10mm with fy = 276Mpa. a.) Determine the minimum thickness of the 1 way slab.(answer in millimeter in whole number) b.) Determine the Ultimate loading combination for the slab considering 1 meter strip?(answer in KN/m. in 3 decimal places ) c.) Determine the Ultimate moment for the slab considering 1 meter strip?(answer in KN-m. in 3 decimal places) d.) Determine the effective depth of the slab considering concrete cover = 20mmanswer in millimeter. in whole number e.) Determine the area of reinforcement for the slab based on the actual loadings.(answer in sq.mm. in 3 decimal places) f.) Determine the spacing of the rebar.(answer in millimeter(Don't round up, use actual value). in 3 decimal places)
B; Design the area, strength design and effective bearing capacity of column footing, if qa= 10ksf, Fc' for footing=5000psi, Fc' for column= 4000psi, fy=40ksi, s.D.L=400k, sL.L=300k nd colum size=1ftx1ft (convert psi to ksi and all necessary unit conversion 5/
A rectangular footing 23 m x 32 m x 0.34 m thick supports a 300 mm square column at its center. Column loads are service conditions: DL = 341 kN LL = 216 kN fc = 21 MPa fy = 415 MPa Concrete cover to the centroid of steel reinforcement = 100 mm Calculate the nominal punching shear stress in the slab Write your final answer with 2 decimal places if the unit is MPA
The slab shown below using f'c= 25 MPa and fy = 420 MPa. The service dead loads are 5 kN/m including its own weight and service live loads are 7 kN/m?: 1- Find area of steel required for the slab. 2- Area of steel required for interior beam B1, at critical section. 6.0 m 6.5 m 6.0 m 0.3m 0.3m 4.5 m 4.5 m 0.3m 0.3m B. 4.5 m 4.5 m 0.3m 0.3m He 6.3m 0.3m 0.3m 0.3m
*Subject: Reinforced prestressed concrete - Civil Engineering *Please refer for my attached formula or guidelines solve this problem A one-way both ends continuous slab is to support the moments tabulated. Consider L=5m, Fc’=21MPa and fy = 415 MPA. Dead load Moments: +42kN.m at midspan ; -67 kN.m at support Live load Moment: +40kN.m at midspan, -44kN.m at support. Determine the minimum thickness of the slab.
Design a simply supported one- way slab with ln=4m. Let fy=276MPa, f’c=21MPa, db=10mm and Cc=20mma. Determine the thickness of the slabb. Determine the required reinforcement spacing and check the for minimum and maximum values set by NSCP.
R1-5. Determine the average punching shear stress the circular shaft creates in the metal plate through section AC and BD. Also, what is the average bearing stress developed on the surface of the plate under the shaft? C 40 KN -50 mm- -60 mm- -120 mm B D $10 mm

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