Column A Column B 1. You are blown over during a windstorm, а. 500,000 Ра presenting a cross-sectional area of 0.5 m2 and feeling a force of 200 lbs. b. 1800 Pa с. 380,000 Ра A 7000-kg elephant stands on you with one foot, an area of 0.18 m2. 2. d. 50,000 Pa

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Chapter1: Units, Trigonometry. And Vectors
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Match the following situations to the resulting pressure.

 
### Match the Following Situations to the Resulting Pressure

#### Column A
1. You are blown over during a windstorm, presenting a cross-sectional area of 0.5 m² and feeling a force of 200 lbs.
2. A 7000-kg elephant stands on you with one foot, an area of 0.18 m².
3. You (60 kg) hold your breath and dive five meters underwater.
4. Pushing a 30-gauge needle (R = 0.159 mm) against your skin with a force of 4 N.

#### Column B
a. 500,000 Pa  
b. 1800 Pa  
c. 380,000 Pa  
d. 50,000 Pa  

---

#### Explanation of Matching:

To solve this exercise, you need to calculate the pressure exerted in each scenario by applying the formula for pressure:

\[ \text{Pressure (Pa)} = \frac{\text{Force (N)}}{\text{Area (m}^2)} \]

- For the underwater scenario, consider the static fluid pressure formula:
  
\[ \text{Pressure due to water (Pa)} = \text{density of water (kg/m}^3) \times \text{gravity (m/s}^2) \times \text{depth (m)} \]

Use these calculations to match each situation in Column A to the correct pressure in Column B.
Transcribed Image Text:### Match the Following Situations to the Resulting Pressure #### Column A 1. You are blown over during a windstorm, presenting a cross-sectional area of 0.5 m² and feeling a force of 200 lbs. 2. A 7000-kg elephant stands on you with one foot, an area of 0.18 m². 3. You (60 kg) hold your breath and dive five meters underwater. 4. Pushing a 30-gauge needle (R = 0.159 mm) against your skin with a force of 4 N. #### Column B a. 500,000 Pa b. 1800 Pa c. 380,000 Pa d. 50,000 Pa --- #### Explanation of Matching: To solve this exercise, you need to calculate the pressure exerted in each scenario by applying the formula for pressure: \[ \text{Pressure (Pa)} = \frac{\text{Force (N)}}{\text{Area (m}^2)} \] - For the underwater scenario, consider the static fluid pressure formula: \[ \text{Pressure due to water (Pa)} = \text{density of water (kg/m}^3) \times \text{gravity (m/s}^2) \times \text{depth (m)} \] Use these calculations to match each situation in Column A to the correct pressure in Column B.
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