Color Yellow (Y) Green (G) Frequency Red (R) 8 Blue (L) Brown (B) 1 8 Orange (0) 7 P(doubles) 15 1 Enter an integer or decimal number [more..] Step 2: Let's find our THEORETICAL probabilities for drawing 2 random M&Ms. Set aside the candy for now. And use what you know about about probability to find the following: (Note that R₁ means a red on the first draw and B₂ means a brown on the second draw, for example) You can leave everything in unreduced fraction form. With Replacement (Independent) Probability P(2 reds) = P(R₁ R₂) P(R₁ B₂ OR B₁ R₂) P(R₁ G₂) P(G₂|R₁) P(no yellows)=P(Y₁ Y 2 Without Replacement (2nd draw depends on the 1st) P(no doubles) Hint: Doubles, add up the probabilities of both same color and no doubles in the complement of
Color Yellow (Y) Green (G) Frequency Red (R) 8 Blue (L) Brown (B) 1 8 Orange (0) 7 P(doubles) 15 1 Enter an integer or decimal number [more..] Step 2: Let's find our THEORETICAL probabilities for drawing 2 random M&Ms. Set aside the candy for now. And use what you know about about probability to find the following: (Note that R₁ means a red on the first draw and B₂ means a brown on the second draw, for example) You can leave everything in unreduced fraction form. With Replacement (Independent) Probability P(2 reds) = P(R₁ R₂) P(R₁ B₂ OR B₁ R₂) P(R₁ G₂) P(G₂|R₁) P(no yellows)=P(Y₁ Y 2 Without Replacement (2nd draw depends on the 1st) P(no doubles) Hint: Doubles, add up the probabilities of both same color and no doubles in the complement of
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
![Color
Yellow (Y)
Green (G)
Orange (0)
Frequency
Red (R)
8
Blue (L)
Brown (B) 1
8
15
7
1
Enter an integer or decimal number [more..]
Step 2: Let's find our THEORETICAL probabilities for drawing 2 random M&Ms. Set aside the candy
for now. And use what you know about about probability to find the following: (Note that R₁ means
a red on the first draw and B2 means a brown on the second draw, for example) You can leave
everything in unreduced fraction form.
Probability
With Replacement
(Independent)
P(2 reds) = P(R₁ R₂)
P(R₁ B₂ OR B₁ R₂)
P(R₁ G₂)
n
P(G₂|R₁)
P(no yellows)=P(Y₁C Y29
P(doubles)
Without Replacement (2nd
draw depends on the 1st)
P(no doubles)
Hint: Doubles, add up the probabilities of both same color and no doubles in the complement of](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe9d8e919-6c53-43b3-96c1-5f9438fdaf13%2F2b033819-2754-4d25-806a-5ae2dddd6981%2F3n6au4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Color
Yellow (Y)
Green (G)
Orange (0)
Frequency
Red (R)
8
Blue (L)
Brown (B) 1
8
15
7
1
Enter an integer or decimal number [more..]
Step 2: Let's find our THEORETICAL probabilities for drawing 2 random M&Ms. Set aside the candy
for now. And use what you know about about probability to find the following: (Note that R₁ means
a red on the first draw and B2 means a brown on the second draw, for example) You can leave
everything in unreduced fraction form.
Probability
With Replacement
(Independent)
P(2 reds) = P(R₁ R₂)
P(R₁ B₂ OR B₁ R₂)
P(R₁ G₂)
n
P(G₂|R₁)
P(no yellows)=P(Y₁C Y29
P(doubles)
Without Replacement (2nd
draw depends on the 1st)
P(no doubles)
Hint: Doubles, add up the probabilities of both same color and no doubles in the complement of
Expert Solution
Step 1:-
Given that, the Frequency of red is 1.
Total Frequency is n= 40
Then the Probability that first M&M is red,
P(R1)= 1/40
We put red M&M back and again draw then the Probability of drawing red one is
P(R2)= 1/40
So With replacement, P(R1 n R2)= P(R1)*P(R2)= (1/40)*(1/40)= 1/1600
Without replacement:
After drawing first M&M, if it's red then Probability of again drawing red is 0.
So without replacement, P(R1 n R2)= (1/40)*0= 0
Step by step
Solved in 7 steps
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