Collision 2 (M₁ >> M₂) 4 extra masses on M₁ M₁ M₂ 401.27 = 191.6 g = Mass 0.40127 kg 0.1916 kg Initial Time 0.0942 s 0 Initial Velocity 1.0616 m/s 0 m/s Final Time 0.4371 s 0.1339 s Final Velocity 0.2288 m/s 0.7468 m/s Initial Momentum Final M1 = 0.4260 m1 = 0.092 Momentum
Collision 2 (M₁ >> M₂) 4 extra masses on M₁ M₁ M₂ 401.27 = 191.6 g = Mass 0.40127 kg 0.1916 kg Initial Time 0.0942 s 0 Initial Velocity 1.0616 m/s 0 m/s Final Time 0.4371 s 0.1339 s Final Velocity 0.2288 m/s 0.7468 m/s Initial Momentum Final M1 = 0.4260 m1 = 0.092 Momentum
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University Physics 1 - Conservation of Momentum
I need help with this problem and an explanation of the solutions described below:
Pick one of the collisions (identify which one it is) from the air track collision experiment.
Collision 2 ( described in the image below)
and calculate the mechanical energy both before and after the collision. Was energy lost or gained? If it was lost, where did it go? If it was gained, where did it come from?

Transcribed Image Text:Collision 2 (M₁ >> M₂)
4 extra masses on M₁
M₁
M₂
401.27 =
191.6 g =
Mass
0.40127 kg
0.1916 kg
Initial Time
0.0942 s
0
Initial Velocity
1.0616 m/s
0 m/s
Final Time
0.4371 s
0.1339 s
Final Velocity
0.2288 m/s 0.7468 m/s
Initial
Momentum
Final
M1 = 0.4260
m1 = 0.092
Momentum
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