Co(H2O)62++ 4 Cl–=CoCl42–+ 6H2O    (pink)                     (blue) When cobalt(II) chloride is added to pure water, the Co2+ ions hydrate. The hydrated form then reacts with the Cl– ions to set up the equilibrium shown here. a. Describe the change that the system will undergo if 12M hydrochloric acid is added? b. Describe the change that the system will undergo if silver nitrate is added? c. For the equilibrium of this reaction to truly be observed, the cobalt (II) chloride is dissolved in ethanol, rather than using water as the solvent. Why is this the necessary?

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Co(H2O)62++ 4 Cl=CoCl42–+ 6H2O

   (pink)                     (blue)

When cobalt(II) chloride is added to pure water, the Co2+ ions hydrate. The hydrated form then reacts with the Cl ions to set up the equilibrium shown here.

a. Describe the change that the system will undergo if 12M hydrochloric acid is added?

b. Describe the change that the system will undergo if silver nitrate is added?

c. For the equilibrium of this reaction to truly be observed, the cobalt (II) chloride is dissolved in ethanol, rather than using water as the solvent. Why is this the necessary?

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