Cognitive science consistently shows that one of the most effective studying tools is to self-test. A recent study reinforced this finding. In the study, college students studied pairs of Swahili and English words. All students had the same initial study time and then three blocks of practice time. During the practice time, half the students studied the words by reading them side-by-side, while the other half gave themselves quizzes in which they were shown one word and had to recall its partner. Students were randomly assigned to the two groups. On the final test one week later, the proportion of items correctly recalled was 15% for the reading-study group and 42% for the self-quiz group. Assume conditions are met for using a Normal distribution. Test whether giving self-quizzes is more effective and show all details of the test. 1. State hypotheses. 2. The standard error for the difference in proportions is SE= 0.0723. Calculate the z-statistic. Z= 3. Find the p-value using Statkey. 4. State a conclusion in context of the question, using nontechnical language. 5. Find and interpret a 99% confidence interval to estimate the magnitude of the benefits of self- quizzing over reading. Use the standard error estimate SE= 0.0785.

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Cognitive science consistently shows that one of the most effective studying tools is to self-test. A
recent study reinforced this finding. In the study, college students studied pairs of Swahili and
English words. All students had the same initial study time and then three blocks of practice time.
During the practice time, half the students studied the words by reading them side-by-side, while
the other half gave themselves quizzes in which they were shown one word and had to recall its
partner. Students were randomly assigned to the two groups.
On the final test one week later, the proportion of items correctly recalled was 15% for the
reading-study group and 42% for the self-quiz group. Assume conditions are met for using a
Normal distribution.
Test whether giving self-quizzes is more effective and show all details of the test.
1. State hypotheses.
2. The standard error for the difference in proportions is SE= 0.0723. Calculate the z-statistic.
Z=
3. Find the p-value using Statkey.
4. State a conclusion in context of the question, using nontechnical language.
5. Find and interpret a 99% confidence interval to estimate the magnitude of the benefits of self-
quizzing over reading. Use the standard error estimate SE= 0.0785.
Transcribed Image Text:Cognitive science consistently shows that one of the most effective studying tools is to self-test. A recent study reinforced this finding. In the study, college students studied pairs of Swahili and English words. All students had the same initial study time and then three blocks of practice time. During the practice time, half the students studied the words by reading them side-by-side, while the other half gave themselves quizzes in which they were shown one word and had to recall its partner. Students were randomly assigned to the two groups. On the final test one week later, the proportion of items correctly recalled was 15% for the reading-study group and 42% for the self-quiz group. Assume conditions are met for using a Normal distribution. Test whether giving self-quizzes is more effective and show all details of the test. 1. State hypotheses. 2. The standard error for the difference in proportions is SE= 0.0723. Calculate the z-statistic. Z= 3. Find the p-value using Statkey. 4. State a conclusion in context of the question, using nontechnical language. 5. Find and interpret a 99% confidence interval to estimate the magnitude of the benefits of self- quizzing over reading. Use the standard error estimate SE= 0.0785.
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