CO(g) + H2O(g) CO2(g) + H2(g) The standard formation free energies of the substances in the equilibrium reaction at cons- tant pressure are given below in kcal mol1. AG co (298) = -32,81 ; AG;H0(298) =-54,64 ; AGico, (298) = -94,26 a) What is the equilibrium constant of the reaction at 298 K? b) In which direction does the reaction proceed at 298K in a mixture where the partial pressures of the substances at equilibrium are Pco = 0.1atm, Pco. = 0,03atm PH0 = 0,02atm , P = 0,2atm ? c) Since the standard reaction entropy is -10.13 cal / K, what is the equilibrium constant at 125°C? dlnk = (AH° / RT² ) dT

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CO(g) + H20(g)
CO2(g) + H2(g)
The standard formation free energies of the substances in the equilibrium reaction at cons-
tant pressure are given below in kcal mol1.
AG:co (298) = -32,81 ; AGH,0(298) =-54,64 ; AG,co, (298) = -94,26
a) What is the equilibrium constant of the reaction at 298 K?
b) In which direction does the reaction proceed at 298K in a mixture where the partial
pressures of the substances at equilibrium are Pco = 0.1atm, Pco. = 0,03atm
PH0 = 0,02atm, PH = 0,2atm ?
c) Since the standard reaction entropy is -10.13 cal / K, what is the equilibrium constant
at 125°C?
dlnk = (AH° / RT² ) dT
Transcribed Image Text:CO(g) + H20(g) CO2(g) + H2(g) The standard formation free energies of the substances in the equilibrium reaction at cons- tant pressure are given below in kcal mol1. AG:co (298) = -32,81 ; AGH,0(298) =-54,64 ; AG,co, (298) = -94,26 a) What is the equilibrium constant of the reaction at 298 K? b) In which direction does the reaction proceed at 298K in a mixture where the partial pressures of the substances at equilibrium are Pco = 0.1atm, Pco. = 0,03atm PH0 = 0,02atm, PH = 0,2atm ? c) Since the standard reaction entropy is -10.13 cal / K, what is the equilibrium constant at 125°C? dlnk = (AH° / RT² ) dT
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