[Co(CN):(OH;)J* + [Co(NH3)s(NCS)}* = [Co(CN):(SCN)]* + [Co(OH,);F* 3. Explain why, in the products of this reaction, one of the cobalt centers has lost all of the ammonia ligands initially attached to it.

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[Co(CN):(OH,))* + [Co(NH,)s(NCS)}* = [Co(CN):(SCN)J* + [Co(OH,)JF*
3. Explain why, in the products of this reaction, one of the cobalt centers has lost ll
of the ammonia ligands initially attached to it.
4. Draw the Lewis structure for the SCN' ligand and explain the two different ways
that it can function as a bridging ligand.
5. In the redox reactions between [Co(CN):(OH2)J®* and both linkage isomers of
[Co(NH3)s(SCN)]**, [[Co(CN);(SCN)]* is one of the products formed. Please draw
the two different bridged intermediates (one that results from the reaction of each
linkage isomer) that lead to the single S-bonded product.
6. In the redox reaction between [Co(NH3)(SCN)]²* and [Cr(OH2)]*, both remote
and adjacent attack on the SCN' ligand can occur, resulting in the formation of
[Cr(OH;)s(NCS)]** and [Cr(OH)s(SCN)]*, respectively. When [Co(NH3)s(NCS)]}*
is used, only [Cr(OH)s(SCN)]²* is formed. Please explain these results.
Transcribed Image Text:[Co(CN):(OH,))* + [Co(NH,)s(NCS)}* = [Co(CN):(SCN)J* + [Co(OH,)JF* 3. Explain why, in the products of this reaction, one of the cobalt centers has lost ll of the ammonia ligands initially attached to it. 4. Draw the Lewis structure for the SCN' ligand and explain the two different ways that it can function as a bridging ligand. 5. In the redox reactions between [Co(CN):(OH2)J®* and both linkage isomers of [Co(NH3)s(SCN)]**, [[Co(CN);(SCN)]* is one of the products formed. Please draw the two different bridged intermediates (one that results from the reaction of each linkage isomer) that lead to the single S-bonded product. 6. In the redox reaction between [Co(NH3)(SCN)]²* and [Cr(OH2)]*, both remote and adjacent attack on the SCN' ligand can occur, resulting in the formation of [Cr(OH;)s(NCS)]** and [Cr(OH)s(SCN)]*, respectively. When [Co(NH3)s(NCS)]}* is used, only [Cr(OH)s(SCN)]²* is formed. Please explain these results.
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