Classify each addition as either syn or anti. Br Br₂ Rxn I CH3 Me HBr Rxn II Et Rxn II anti syn anti syn CI Me Rxn I A. syn B. syn C. anti D. anti Cl UI H Me Br Me 'Br Et

Organic Chemistry: A Guided Inquiry
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Author:Andrei Straumanis
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Chapter13: Substitution
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### Classify Each Addition as Either Syn or Anti

When analyzing reactions, it is crucial to classify the stereochemistry of the addition products. In this exercise, we will determine whether the addition reactions proceed via a syn or anti mechanism.

#### Reaction I (Rxn I):
1. **Reactant:** Cyclopentene
2. **Reagent:** Bromine (Br₂)
3. **Product:** A dibromocyclopentane where the two bromine atoms are added across the double bond.

#### Reaction II (Rxn II):
1. **Reactant:** 3-Chloro-2-methyl-2-butene
2. **Reagent:** Hydrobromic Acid (HBr)
3. **Product:** A resultant molecule with an additional hydrogen and bromine on the previously double-bonded carbons.

### Stereochemistry Options:
Below are the possible classifications for these reactions, indicating whether they proceed via syn or anti addition:

1. **A.**
   - **Rxn I:** syn
   - **Rxn II:** anti
2. **B.**
   - **Rxn I:** syn
   - **Rxn II:** syn
3. **C.**
   - **Rxn I:** anti
   - **Rxn II:** anti
4. **D.**
   - **Rxn I:** anti
   - **Rxn II:** syn

### Explanation of Graphs/Diagrams:
- **Diagram for Rxn I:** 
  - **Reactant:** The cyclopentene is represented with a double bond within the five-membered ring.
  - **Product:** The addition of bromine atoms is shown on the opposite sides of the ring structure, indicating an anti addition.

- **Diagram for Rxn II:**
  - **Reactant:** The 3-chloro-2-methyl-2-butene is depicted with a double bond between the second and third carbon, and substituents (Chlorine, methyl, and ethyl) attached to these carbons.
  - **Product:** Hydrogen and bromine have been added across the double bond. The hydrogen adds on the same side as the chlorine (syn addition) and the bromine is on the same carbon as the ethyl group.

### Conclusion:
Based on the product structures:
- **Rxn I:** Exhibits anti addition due to the trans configuration of the added Br atoms
Transcribed Image Text:### Classify Each Addition as Either Syn or Anti When analyzing reactions, it is crucial to classify the stereochemistry of the addition products. In this exercise, we will determine whether the addition reactions proceed via a syn or anti mechanism. #### Reaction I (Rxn I): 1. **Reactant:** Cyclopentene 2. **Reagent:** Bromine (Br₂) 3. **Product:** A dibromocyclopentane where the two bromine atoms are added across the double bond. #### Reaction II (Rxn II): 1. **Reactant:** 3-Chloro-2-methyl-2-butene 2. **Reagent:** Hydrobromic Acid (HBr) 3. **Product:** A resultant molecule with an additional hydrogen and bromine on the previously double-bonded carbons. ### Stereochemistry Options: Below are the possible classifications for these reactions, indicating whether they proceed via syn or anti addition: 1. **A.** - **Rxn I:** syn - **Rxn II:** anti 2. **B.** - **Rxn I:** syn - **Rxn II:** syn 3. **C.** - **Rxn I:** anti - **Rxn II:** anti 4. **D.** - **Rxn I:** anti - **Rxn II:** syn ### Explanation of Graphs/Diagrams: - **Diagram for Rxn I:** - **Reactant:** The cyclopentene is represented with a double bond within the five-membered ring. - **Product:** The addition of bromine atoms is shown on the opposite sides of the ring structure, indicating an anti addition. - **Diagram for Rxn II:** - **Reactant:** The 3-chloro-2-methyl-2-butene is depicted with a double bond between the second and third carbon, and substituents (Chlorine, methyl, and ethyl) attached to these carbons. - **Product:** Hydrogen and bromine have been added across the double bond. The hydrogen adds on the same side as the chlorine (syn addition) and the bromine is on the same carbon as the ethyl group. ### Conclusion: Based on the product structures: - **Rxn I:** Exhibits anti addition due to the trans configuration of the added Br atoms
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