class Solution(object): def merge(self, intervals): intervals.sort(key=lambda x: x[0]) merged = [] for interval in intervals: if not merged or merged[-1][1] < interval[0]: merged.append(interval) else: merged[-1][1] = max(merged[-1][1], interval[1]) return merged give a detailed 2-3 sentence analysis of the time complexity and space complexity of this algorithm in big O notation
class Solution(object): def merge(self, intervals): intervals.sort(key=lambda x: x[0]) merged = [] for interval in intervals: if not merged or merged[-1][1] < interval[0]: merged.append(interval) else: merged[-1][1] = max(merged[-1][1], interval[1]) return merged give a detailed 2-3 sentence analysis of the time complexity and space complexity of this algorithm in big O notation
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Question
class Solution(object):
def merge(self, intervals):
intervals.sort(key=lambda x: x[0])
merged = []
for interval in intervals:
if not merged or merged[-1][1] < interval[0]:
merged.append(interval)
else:
merged[-1][1] = max(merged[-1][1], interval[1])
return merged
give a detailed 2-3 sentence analysis of the time complexity and space complexity of this algorithm in big O notation
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