/* Class representing a directed graph using adjacency lists +/ static class Graph { int V; //Number of Vertices LinkedList [] adj; // adjacency lists //Constructor Graph(int V) this.V = V; adj = new LinkedList (V]; for (int i = 0; i < adj.length; i++) adj[i] = new LinkedList(); //To add an edge to graph void addEdge (int v, int w) { adj [v].add (w); // Add w to the list of v.
/* Class representing a directed graph using adjacency lists +/ static class Graph { int V; //Number of Vertices LinkedList [] adj; // adjacency lists //Constructor Graph(int V) this.V = V; adj = new LinkedList (V]; for (int i = 0; i < adj.length; i++) adj[i] = new LinkedList(); //To add an edge to graph void addEdge (int v, int w) { adj [v].add (w); // Add w to the list of v.
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Java
Pleasse add Comments and Test-Cases to code.
explore a specific way to perform a Breadth First Search (BFS) of a given Graph [ Figure 1].
![2
4
5
Figure 1: Graph for Traversal
/* Class representing a directed graph using adjacency lists */
static class Graph
int V; //Number of Vertices
LinkedList<Integer> [] adj; // adjacency lists
//Constructor
Graph (int V)
{
this.V = V;
adj - new LinkedList [V];
for (int i = 0; i < adj.length; i++)
adj [i] = new LinkedList<Integer>();
//To add an edge to graph
void addEdge (int v, int w)
{
adj [v].add (w); // Add w to the list of v.
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc353cc0f-0c4d-4d5b-a3e6-e746dbb90f94%2Ff4df5066-8b1a-4b48-bdec-02ac6ef5140d%2F5l5grnq_processed.png&w=3840&q=75)
Transcribed Image Text:2
4
5
Figure 1: Graph for Traversal
/* Class representing a directed graph using adjacency lists */
static class Graph
int V; //Number of Vertices
LinkedList<Integer> [] adj; // adjacency lists
//Constructor
Graph (int V)
{
this.V = V;
adj - new LinkedList [V];
for (int i = 0; i < adj.length; i++)
adj [i] = new LinkedList<Integer>();
//To add an edge to graph
void addEdge (int v, int w)
{
adj [v].add (w); // Add w to the list of v.
2
Transcribed Image Text:The edges of the Graph is given to you.
g. addEdge (0, 1);
g. addEdge (0, 2);
g. addEdge (2, 3);
g. addEdge (2, 4);
g. addEdge (4, 5);
g. addEdge (1, 3);
g. addEdge (3, 5);
Your code will need to return the traversal of the nodes in BFS order, where
the traversal starts from Node/Vertex 0.
When you follow the traversal process as specified - the complexity of the solu-
tion will be linear as shown below.
Time Complexity: 0(V + E), where V is the number of Vertices and
E is the number of Edges respectively.
Space Complexity: 0(V)
The linear space complexity would come from the specific data structure you
employ to traverse the Graph using BFS.
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