The edges of the Graph is given to you. g. addEdge (0, 1); g. addEdge (0, 2); g. addEdge (2, 3); g. addEdge (2, 4); g. addEdge (4, 5); g. addEdge (1, 3); g. addEdge (3, 5); Your code will need to return the traversal of the nodes in BFS order, where the traversal starts from Node/Vertex 0. When you follow the traversal process as specified - the complexity of the solu- tion will be linear as shown below. Time Complexity: 0(V +E), where V is the number of Vertices and E is the number of Edges respectively. Space Complexity: 0(V) The linear space complexity would come from the specific data structure you
The edges of the Graph is given to you. g. addEdge (0, 1); g. addEdge (0, 2); g. addEdge (2, 3); g. addEdge (2, 4); g. addEdge (4, 5); g. addEdge (1, 3); g. addEdge (3, 5); Your code will need to return the traversal of the nodes in BFS order, where the traversal starts from Node/Vertex 0. When you follow the traversal process as specified - the complexity of the solu- tion will be linear as shown below. Time Complexity: 0(V +E), where V is the number of Vertices and E is the number of Edges respectively. Space Complexity: 0(V) The linear space complexity would come from the specific data structure you
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Java
Very important: As a COMMENT IN CODE, please DO Test-Cases on how you would test your solution assumptions and hence your code
explore a specific way to perform a Breadth First Search (BFS) of a given Graph [Figure 1].
Transcribed Image Text:The edges of the Graph is given to you.
g. addEdge (0, 1);
g. addEdge (0, 2);
g. addEdge (2, 3);
g. addEdge (2, 4);
g. addEdge (4, 5);
g. addEdge (1, 3);
g. addEdge (3, 5);
Your code will need to return the traversal of the nodes in BFS order, where
the traversal starts from Node/Vertex 0.
When you follow the traversal process as specified - the complexity of the solu-
tion will be linear as shown below.
Time Complexity: 0(V + E), where V is the number of Vertices and
E is the number of Edges respectively.
Space Complexity: 0(V)
The linear space complexity would come from the specific data structure you
employ to traverse the Graph using BFS.
![2
4
5
Figure 1: Graph for Traversal
/* Class representing a directed graph using adjacency lists */
static class Graph
int V; //Number of Vertices
LinkedList<Integer> [] adj; // adjacency lists
//Constructor
Graph (int V)
{
this.V = V;
adj - new LinkedList [V];
for (int i = 0; i < adj.length; i++)
adj [i] = new LinkedList<Integer>();
//To add an edge to graph
void addEdge (int v, int w)
{
adj [v].add (w); // Add w to the list of v.
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc353cc0f-0c4d-4d5b-a3e6-e746dbb90f94%2F14d28008-1599-47c8-9f46-94efb7b5ca3f%2F4r2yc3b_processed.png&w=3840&q=75)
Transcribed Image Text:2
4
5
Figure 1: Graph for Traversal
/* Class representing a directed graph using adjacency lists */
static class Graph
int V; //Number of Vertices
LinkedList<Integer> [] adj; // adjacency lists
//Constructor
Graph (int V)
{
this.V = V;
adj - new LinkedList [V];
for (int i = 0; i < adj.length; i++)
adj [i] = new LinkedList<Integer>();
//To add an edge to graph
void addEdge (int v, int w)
{
adj [v].add (w); // Add w to the list of v.
2
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