Claim: A Frosted Fruits cereal box contains more than 16 ounces of cereal. A random sample of 12 revealed a mean of 17.93 ounces and a sample standard deviation of 2.08. Use the p-value method at a 1% significance level to test the daim. α- [three decimal accuracy] p-value = [three decimal accuracy] Conclusion O Fail to Reject Ho O Reject Ho

Claim: A Frosted Fruits cereal box contains more than 16 ounces of cereal. A random sample of 12 revealed a mean of 17.93 ounces and a sample standard deviation of 2.08. Use the p-value method at a 1% significance level to test the daim. α- [three decimal accuracy] p-value = [three decimal accuracy] Conclusion O Fail to Reject Ho O Reject Ho

Name: Claim: A Frosted Fruits cereal box contains more than 16 ounces of ce
Uploaded: 2024-03-20T07:07:12.000Z
Channel: Bartleby
Description: Claim: A Frosted Fruits cereal box contains more than 16 ounces of cereal.A random sample of 12 revealed a mean of 17.93 ounces and a sample standard deviation of 2.08. Use thep-value method at a 1% significance level to test the daim.a =[three deci

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

2-find the tast statistic 3- find p-value 4- what is an appropriate conclusion for the test?
You want to test the speed of your internet connection. You will test the claim that your average speed is greater than 4.3 Mb/s. You collect data 39 different times, and among that sample, the average speed is 4.9 Mb/s. Assume internet speeds are normally distributed with a standard deviation of 1.1 Mb/s.a. State the null and alternative hypothesis for the claim that your average speed is greater than 4.3 Mb/s. Ho: ? ___4.3 Ha: ? ___ 4.3 Please explain to me how you determine the sign that goes into the blank space. b. The (null or alternative) hypothesis is the claim c. The goal of the test is to (support or reject) the claim.
Test the claim that a certain x-ray machine gives radiation dosages with a mean below 5.00 milliroentgens. Sample data consist of 28 observations with a mean of 4.16 milliroentgens and a standard deviation of 1.91 milliroentgens. Use a 0.01 level of significance.
Identity the null and alternative hypotheses, test statistic, p value, state final conclusion
Assume the height of a particular species of horse are normally distributed. A random sample of 7 horses has a mean height of 46.14 cm and a standard deviation of 1.19 cm. At a 0.05 level of significance, a test is undertaken to determine whether there is sufficient evidence to reject the claim of a mean height is higher than 45 cm. What statement can be made about the p-value?
The mean score on a driving exam for a group of driver’s education students is 76 points, with a standard deviation of 6 points. Apply chebychev’s theorem to the data using K=2. Interpret, At least ___% of the exam score falls between ___and ____
In a random sample of 12 people,the mean driving distance to work was 23.5 miles and the standard deviation was 6.8.Asume the population is normally distributed to find the margin of error and construct a 95% confidence for population μ.Interpret results.
Determine if the outcome is unusual. Consider as unusual any result that differs from the mean by more than 2 standard deviations. That is, unusual values are either less than u - 20 or greater than u + 20. According to AccuData Media Research, 36% of televisions within the Chicago city limits are tuned to "Eyewitness News" at 5:00 pm on Sunday nights. At 5:00 pm on a given Sunday, 2500 such televisions are randomly selected and checked to determine what is being watched. Would it be unusual to find that 981 of the 2500 televisions are tuned to "Eyewitness News"? Yes O No
Claim: Carzz Magazine daims that the Civic Hybrid gets under 38 mpg on the highway. A random sample of 9 revealed a mean of 37.42222 mpg and a sample standard deviation of 0.92436. Use the traditional method at a 2.5% significance level to test the daim. Critical Value = [three decimal accuracy] Test Statistic = [three decimal accuracy] Conclusion Fail to Reject Ho O Reject Ho
Claim: The average amount of money lost by a casino patron greater then $500. A random sample of 55 revealed a mean of 511.45 dollars. Use the tradi tional method at a 2% significance level to test the daim assuming a known population standard deviation of 55. Critical Value = [three decimal accuracy] Test Statistic = [three decimal accuracy] Conclusion Reject Ho O Fail to Reject Ho
Assume the average amount of days a patient spends in hospital is believed to be 24 days and a hospital claims that their experience suggests that the average is actually lower. They randomly selected and followed 33 patients and found that the mean number of days was 21.5 with a standard deviation of 7.8. What is the test statistic and your conclusion for a=0.05? O A. Test statistic: -1.841 Conclusion: Not enough evidence to reject the null hypothesis O B. Test statistic: 1.841 Conclusion: Not enough evidence to reject the null hypothesis O C. Test statistic: 1.841 Conclusion: Reject the null hypothesis D. Test statistic: -1.841 Conclusion: Reject the null hypothesis
6. Test a claim that the mean amount of lead in the air in U.S. cities is less than 0.035 microgram per cubic meter. It was found that the mean amount of lead in the air for the random sample of 58 U.S. cities is 0.038 microgram per cubic meter and the standard deviation is 0.069 microgram per cubic meter. At a = 0.10, can the claim be supported? Complete parts (a) through (e) below. Assume the population is normally distributed. (a) Identify the claim and state Ho and Ha Ho: (1) На (3) (4) (Type integers or decimals. Do not round.) The claim is the (5) hypothesis. (b) Find the critical value(s) and identify the rejection region(s). The critical value(s) is/are to = (Use a comma to separate answers as needed. Round to two decimal places as needed.) Choose the graph which shows the rejection region. OA. OB. OC. OD. - to to t to (c) Find the standardized test statistic, t. The standardized test statistic is t= (Use a comma to separate answers as needed. Round to two decimal places as…