Cl₂ + m Obubbles are produced a white solid forms O a yellow solid forms a blue solid forms ✔a brown solid forms O a gray/silver solid forms Ono visible reaction Yes No chemPad XX 2AI+ 3CuCl₂ → 2AICI3 + 3Cu 2A1+ 3CUCI_2->2AICI3 + 3Cu net ionic equation: Greek- Your answer contains an improperly or incompletely formatted chemical formula. Your answer is missing one or more subscripts or superscripts. chemPad XX- 2A1+ 3Cu2+ 2A1³+ 2AI + 3Cu^2+ --> 2A1^3+ Greek - Help Your answer contains an ambiguous or incomplete reaction equation. Check all the components on the product-side of the equation. Help

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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0.1 M CuCl₂ +
aluminum
U
DUO
bubbles are produced
a white solid forms
a yellow solid forms
a blue solid forms
a brown solid forms
a gray/silver solid forms
no visible reaction
Yes
No
full reaction:
chemPad
XX
2AI+ 3CuCl₂ → 2AICI3 + 3Cu
2AI +3CUCI_2 -->2AICI3 + 3Cu
→=T
net ionic equation:
Your answer contains an improperly or incompletely formatted chemical formula. Your answer is missing one
or more subscripts or superscripts.
chemPad
XX →
2AI + 3Cu2+
2AI + 3Cu^2+ --> 2A1^3+
13+
Greek -
2A1-
Greek -
Help
Your answer contains an ambiguous or incomplete reaction equation. Check all the components on the
product-side of the equation.
Help
Transcribed Image Text:0.1 M CuCl₂ + aluminum U DUO bubbles are produced a white solid forms a yellow solid forms a blue solid forms a brown solid forms a gray/silver solid forms no visible reaction Yes No full reaction: chemPad XX 2AI+ 3CuCl₂ → 2AICI3 + 3Cu 2AI +3CUCI_2 -->2AICI3 + 3Cu →=T net ionic equation: Your answer contains an improperly or incompletely formatted chemical formula. Your answer is missing one or more subscripts or superscripts. chemPad XX → 2AI + 3Cu2+ 2AI + 3Cu^2+ --> 2A1^3+ 13+ Greek - 2A1- Greek - Help Your answer contains an ambiguous or incomplete reaction equation. Check all the components on the product-side of the equation. Help
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