Figure 1 Pressurized tank Z3 pump Different diameters See figure 3 See figure 2 motor At point 2 Figure 2 V1 Stagnation point At points 4 and 5 Figure 3 D5 D4 y With the schematic diagram of a pump, tanks, and piping determine the following: 1) The velocity of the liquid at point 2 (ft/s) 2) Pump work used by the liquid (Wpump U) (hp) 3) Electric motor power in out (kVW) 4) In figure 3, the shaded (pink) in the U tube is mercury; determine y. specific gravity of mercury 13.7 5) Mass flow rate Assume the whole system is steady flow with no friction loss in the pipes and tank. Use only the following constant and conversion g= 32.2 ft/s 1 hp= 33,000 ft-Ibf/min 1 hp = 0.746 kW Specific gracity of mercury 13.7 In computing for the density of mercury use the density of water =62.4 lbm/ft³ Do not convert English units to SI units except horsepower to kW Given: in in ft psia psia in in ft 1 3.1 2.1 0.7 0.51 14.1 45 60 4.1 2.1 25 Seat Number Diameter of pipe in point 1 Diameter of pipe in point 2 Specific gravity of the liquid h (ft) (see figure 2) Pressure at point 1 Pressure at point 2 Pump and motor efficiency Diameter of pipe in point 4 Diameter of pipe in point 5 Z3 (see figure 1)

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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Figure 1
Pressurized tank
Z3
pump
Different diameters
See figure 3
See figure 2
motor
At point 2
Figure 2
V1
Stagnation
point
At points 4 and 5
Figure 3
D5
D4
y
Transcribed Image Text:Figure 1 Pressurized tank Z3 pump Different diameters See figure 3 See figure 2 motor At point 2 Figure 2 V1 Stagnation point At points 4 and 5 Figure 3 D5 D4 y
With the schematic diagram of a pump, tanks, and piping determine the following:
1) The velocity of the liquid at point 2 (ft/s)
2) Pump work used by the liquid (Wpump U) (hp)
3) Electric motor power in out (kVW)
4) In figure 3, the shaded (pink) in the U tube is mercury; determine y. specific gravity of mercury 13.7
5) Mass flow rate
Assume the whole system is steady flow with no friction loss in the pipes and tank.
Use only the following constant and conversion
g= 32.2 ft/s
1 hp= 33,000 ft-Ibf/min
1 hp = 0.746 kW
Specific gracity of mercury 13.7
In computing for the density of mercury use the density of water =62.4 lbm/ft³
Do not convert English units to SI units except horsepower to kW
Given:
in
in
ft
psia
psia
in
in
ft
1
3.1
2.1
0.7
0.51
14.1
45
60
4.1
2.1
25
Seat Number
Diameter of pipe in point 1
Diameter of pipe in point 2
Specific gravity of the liquid
h (ft) (see figure 2)
Pressure at point 1
Pressure at point 2
Pump and motor efficiency
Diameter of pipe in point 4
Diameter of pipe in point 5
Z3 (see figure 1)
Transcribed Image Text:With the schematic diagram of a pump, tanks, and piping determine the following: 1) The velocity of the liquid at point 2 (ft/s) 2) Pump work used by the liquid (Wpump U) (hp) 3) Electric motor power in out (kVW) 4) In figure 3, the shaded (pink) in the U tube is mercury; determine y. specific gravity of mercury 13.7 5) Mass flow rate Assume the whole system is steady flow with no friction loss in the pipes and tank. Use only the following constant and conversion g= 32.2 ft/s 1 hp= 33,000 ft-Ibf/min 1 hp = 0.746 kW Specific gracity of mercury 13.7 In computing for the density of mercury use the density of water =62.4 lbm/ft³ Do not convert English units to SI units except horsepower to kW Given: in in ft psia psia in in ft 1 3.1 2.1 0.7 0.51 14.1 45 60 4.1 2.1 25 Seat Number Diameter of pipe in point 1 Diameter of pipe in point 2 Specific gravity of the liquid h (ft) (see figure 2) Pressure at point 1 Pressure at point 2 Pump and motor efficiency Diameter of pipe in point 4 Diameter of pipe in point 5 Z3 (see figure 1)
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Given Data:

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Given Data:

Diameter of the pipe at point 1 d1=3.1 in=3.112=0.258 ft

Diameter of the pipe at point 2 d2=3.1 in=2.112=0.175 ft

The specific gravity of the liquid SL=0.7

Difference between the height of liquid in both pipe h=0.51 ft

Pressure at  point 1 P1=14.1 psi =14.1×144=2030.4 lbmft2

Pressure at  point 2 P2=45 psi=45×144=6480 lbmft2

Head at point 3 z3=25 ft

The efficiency of pump and motor η=0.60

 

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