City X is 15 kilometers due north of City Y. City Z is 36 kilometers due east of City Y. 6. X W E 15 km Y 36 km What is the straight-line distance from City X to City Z? A. 32 km B. 36 km C. 39 km D. 51 km

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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### Problem Statement
City X is 15 kilometers due north of City Y. City Z is 36 kilometers due east of City Y.

![XYZ Diagram](link-to-diagram-if-any)

### Question
What is the straight-line distance from City X to City Z?

### Explanation with Diagram
We are given three cities X, Y, and Z and their relative positions. The problem provides the following distances:
- City X is 15 kilometers north of City Y.
- City Z is 36 kilometers east of City Y.

In the accompanying diagram, the cities and routes form a right triangle:
- Line segment XY represents the distance from City Y to City X which is 15 kilometers.
- Line segment YZ represents the distance from City Y to City Z which is 36 kilometers.
- Line segment XZ is the hypotenuse of the right triangle, representing the straight-line distance we need to find.

```
  X
  |
15km
  |
  |
  Y ------------------- Z
          36km
```
### Solution
To find the straight-line distance from City X to City Z, we can use the Pythagorean theorem. The Pythagorean theorem is stated as:

\[ a^2 + b^2 = c^2 \]

where \(a\) and \(b\) are the lengths of the legs of a right triangle, and \(c\) is the length of the hypotenuse.

Here, \( a = 15 \) km and \( b = 36 \) km. Plugging in these values:
\[ 15^2 + 36^2 = c^2 \]
\[ 225 + 1296 = c^2 \]
\[ 1521 = c^2 \]
\[ c = \sqrt{1521} \]
\[ c = 39 \text{ km} \]

### Answer
The straight-line distance from City X to City Z is 
\[ \boxed{39 \text{ km}} \]

### Multiple Choice Options
A. 32 km  
B. 36 km  
C. 39 km  
D. 51 km  

The correct choice is:
\[ \boxed{C. 39 \text{ km}} \]
Transcribed Image Text:### Problem Statement City X is 15 kilometers due north of City Y. City Z is 36 kilometers due east of City Y. ![XYZ Diagram](link-to-diagram-if-any) ### Question What is the straight-line distance from City X to City Z? ### Explanation with Diagram We are given three cities X, Y, and Z and their relative positions. The problem provides the following distances: - City X is 15 kilometers north of City Y. - City Z is 36 kilometers east of City Y. In the accompanying diagram, the cities and routes form a right triangle: - Line segment XY represents the distance from City Y to City X which is 15 kilometers. - Line segment YZ represents the distance from City Y to City Z which is 36 kilometers. - Line segment XZ is the hypotenuse of the right triangle, representing the straight-line distance we need to find. ``` X | 15km | | Y ------------------- Z 36km ``` ### Solution To find the straight-line distance from City X to City Z, we can use the Pythagorean theorem. The Pythagorean theorem is stated as: \[ a^2 + b^2 = c^2 \] where \(a\) and \(b\) are the lengths of the legs of a right triangle, and \(c\) is the length of the hypotenuse. Here, \( a = 15 \) km and \( b = 36 \) km. Plugging in these values: \[ 15^2 + 36^2 = c^2 \] \[ 225 + 1296 = c^2 \] \[ 1521 = c^2 \] \[ c = \sqrt{1521} \] \[ c = 39 \text{ km} \] ### Answer The straight-line distance from City X to City Z is \[ \boxed{39 \text{ km}} \] ### Multiple Choice Options A. 32 km B. 36 km C. 39 km D. 51 km The correct choice is: \[ \boxed{C. 39 \text{ km}} \]
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