. Write the equation of the line parallel to y = 6X - 1 that passes through the point (-2,1) in slope intercept form. (This question is worth 2 points. 1 point for the correct slope and the other for the correct y intercept.) B iU Font Family - AA A E: E - E •

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Question:**

Write the equation of the line parallel to \( y = 6x - 1 \) that passes through the point \((-2, 1)\) in slope-intercept form. (This question is worth 2 points: 1 point for the correct slope and the other for the correct y-intercept.)

---

**Explanation:**

To find the equation of the line parallel to a given line, you need the following steps:

1. **Identify the Slope:**
   - The slope of the line \( y = 6x - 1 \) is \( 6 \). 
   - Since parallel lines have the same slope, the new line will also have a slope of \( 6 \).

2. **Use the Point-Slope Formula:**
   - With the point \((-2, 1)\) and the slope \(6\), apply the point-slope formula:
   \[
   y - y_1 = m(x - x_1)
   \]
   - Substitute \( m = 6 \), \( x_1 = -2 \), and \( y_1 = 1 \):
   \[
   y - 1 = 6(x + 2)
   \]

3. **Convert to Slope-Intercept Form:**
   - Expand and simplify the equation:
   \[
   y - 1 = 6x + 12 
   \]
   \[
   y = 6x + 13
   \]

Therefore, the equation of the line parallel to \( y = 6x - 1 \) and passing through \((-2, 1)\) is \( y = 6x + 13 \).

This equation is in slope-intercept form, where the slope is \( 6 \) and the y-intercept is \( 13 \).
Transcribed Image Text:**Question:** Write the equation of the line parallel to \( y = 6x - 1 \) that passes through the point \((-2, 1)\) in slope-intercept form. (This question is worth 2 points: 1 point for the correct slope and the other for the correct y-intercept.) --- **Explanation:** To find the equation of the line parallel to a given line, you need the following steps: 1. **Identify the Slope:** - The slope of the line \( y = 6x - 1 \) is \( 6 \). - Since parallel lines have the same slope, the new line will also have a slope of \( 6 \). 2. **Use the Point-Slope Formula:** - With the point \((-2, 1)\) and the slope \(6\), apply the point-slope formula: \[ y - y_1 = m(x - x_1) \] - Substitute \( m = 6 \), \( x_1 = -2 \), and \( y_1 = 1 \): \[ y - 1 = 6(x + 2) \] 3. **Convert to Slope-Intercept Form:** - Expand and simplify the equation: \[ y - 1 = 6x + 12 \] \[ y = 6x + 13 \] Therefore, the equation of the line parallel to \( y = 6x - 1 \) and passing through \((-2, 1)\) is \( y = 6x + 13 \). This equation is in slope-intercept form, where the slope is \( 6 \) and the y-intercept is \( 13 \).
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