Circuit theory I just want the final answer, I don't need the solution steps. I want the solution in less than 30 minutes, please The question is : Q.1) A Y-connected balanced three-phase generator with an impedance of Zs =0.4+j0.3 ohm per phase is connected to a Y-connected balanced load with an impedance of ZL=19+j48 ohm per phase. The line joining the generator and the load has an impedance of Zl=0.6+j0.7 ohm per phase. Assuming a positive sequence for the source voltages and that amplitude of |Van|=204 and its phase angle 30 degree Find: (a) amplitude of the line voltage Vbc, (b) amplitude of the line current Ic, (c) the complex power at the balanced three-phase load. a. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 89641.40 + j 1110.11 VA b. (a) Vb=288.50 V, (b) Ic=2.23 A, (c) S = 14940.23 + j 320.46 VA c. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 846.88 + j 2139.49 VA d. (a) Vb=353.34 V, (b) Ic=5.78 A, (c) S = 44820.70 + j 832.58 VA e. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 6775.04 + j 17115.90 VA f. (a) Vb=288.50 V, (b) Ic=3.85 A, (c) S = 2540.64 + j 6418.46 VA g. (a) Vb=353.34 V, (b) Ic=4.63 A, (c) S = 3387.52 + j 8557.95 VA h. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 4234.40 + j 10697.44 VA
Circuit theory I just want the final answer, I don't need the solution steps. I want the solution in less than 30 minutes, please The question is : Q.1) A Y-connected balanced three-phase generator with an impedance of Zs =0.4+j0.3 ohm per phase is connected to a Y-connected balanced load with an impedance of ZL=19+j48 ohm per phase. The line joining the generator and the load has an impedance of Zl=0.6+j0.7 ohm per phase. Assuming a positive sequence for the source voltages and that amplitude of |Van|=204 and its phase angle 30 degree Find: (a) amplitude of the line voltage Vbc, (b) amplitude of the line current Ic, (c) the complex power at the balanced three-phase load. a. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 89641.40 + j 1110.11 VA b. (a) Vb=288.50 V, (b) Ic=2.23 A, (c) S = 14940.23 + j 320.46 VA c. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 846.88 + j 2139.49 VA d. (a) Vb=353.34 V, (b) Ic=5.78 A, (c) S = 44820.70 + j 832.58 VA e. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 6775.04 + j 17115.90 VA f. (a) Vb=288.50 V, (b) Ic=3.85 A, (c) S = 2540.64 + j 6418.46 VA g. (a) Vb=353.34 V, (b) Ic=4.63 A, (c) S = 3387.52 + j 8557.95 VA h. (a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 4234.40 + j 10697.44 VA
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Circuit theory
I just want the final answer, I don't need the solution steps.
I want the solution in less than 30 minutes, please
The question is :
Q.1) A Y-connected balanced three-phase generator with an impedance of Zs =0.4+j0.3 ohm per phase is connected to a Y-connected balanced load with an impedance of ZL=19+j48 ohm per phase. The line joining the generator and the load has an impedance of Zl=0.6+j0.7 ohm per phase. Assuming a positive sequence for the source voltages and that amplitude of |Van|=204 and its phase angle 30 degree Find:
(a) amplitude of the line voltage Vbc,
(b) amplitude of the line current Ic,
(c) the complex power at the balanced three-phase load.
a.
(a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 89641.40 + j 1110.11 VA
b.
(a) Vb=288.50 V, (b) Ic=2.23 A, (c) S = 14940.23 + j 320.46 VA
c.
(a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 846.88 + j 2139.49 VA
d.
(a) Vb=353.34 V, (b) Ic=5.78 A, (c) S = 44820.70 + j 832.58 VA
e.
(a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 6775.04 + j 17115.90 VA
f.
(a) Vb=288.50 V, (b) Ic=3.85 A, (c) S = 2540.64 + j 6418.46 VA
g.
(a) Vb=353.34 V, (b) Ic=4.63 A, (c) S = 3387.52 + j 8557.95 VA
h.
(a) Vb=353.34 V, (b) Ic=3.85 A, (c) S = 4234.40 + j 10697.44 VA
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