Cigarette Smoking A researcher found that a cigarette smoker smokes onaverage 31 cigarettes a day. She feels that this average is too high. Sheselected a random sample of 10 smokers and found that the mean numberof cigarettes they smoked per day was 28. The sample standard deviationwas 2.7. At a=0.05, is there enough evidence to support her claim? Assumethat the population is approximately normally distributed. Use the P-valuemethod and a TI-83 Plus/TI-84 Plus calculator. State the hypotheses and identify the claim with the correct hypothesis.Ho: (Choose one)H₁:(Choose one) ▼This hypothesis test is a (Choose one) test.

Given information Population mean µ = 31 Sample size (n) = 10 Mean x̅ = 28 Standard deviation (s) =…

Answered: Cigarette Smoking A researcher found…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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The average waiting time in a doctor’s office varies. The standard deviation of waiting times in a doctor’s office is 3.4 minutes. A random sample of 30 patients in the doctor’s office has a standard deviation of waiting times of 4.1 minutes. One doctor believes the variance of waiting times is greater than originally thought.a. What type of test should be used?b. What is the test statistic?c. What is the p-value?d. What can you conclude at the 5% significance level?
Calculate the sample size to study the average age of a Central State College student, plus or minus 0.4 years. We’d like to be 85% confident about our result. From a previous study, we know that the standard deviation for the population is 2.8.
Suppose that the average number of Facebook friends users have is normally distributed with a mean of 145 and a standard deviation of about 57. Assume forty-nine individuals are randomly chosen. Answer the following questions. Round all answers to 4 decimal places where possible. Find the first quartile for the average number of Facebook friends.
One-Way Airfares The average one-way airfare from Pittsburgh to Washington D.C. is $236. A random sample of 19 one-way fares during a particular month had a mean of $208 with a standard deviation of $43. At α=0.05, is there sufficient evidence to conclude a difference from the stated mean?
Students preparing for comprehensive exams usually spend many hours studying. Suppose it is known that the time students spend studying for comprehensive exams has a distribution that is skewed heavily to the right with a mean of 41.3 hours and a standard deviation of 6.8 hours. If a simple random sample of 72 students is selected and the amount of time each spent studying for the comprehensive exam is determined. State and check the two assumptions.
Use z scores to compare the given values. The tallest living man at one time had a height of 238 cm. The shortest living man at that time had a height of 142.4 cm. Heights of men at that time had a mean of 175.45 cm and a standard deviation of 5.59 cm. Which of these two men had the height that was more extreme? ... Since the z score for the tallest man is z = 0 and the z score for the shortest man is z = the man had the height that was Im- more extreme. (Round to two decimal places.) shortest tallest
This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.
. A medical researcher wishes to see whether the pulse rate of smokers are higher than the pulse rates of non-smokers. Samples of 100 smokers and 100 nonsmokers are selected. The results are shown below. Can the researcher conclude at an alpha = 0.05, that smokers have higher pulse rates than nonsmokers? Smokers Non-Smokers Mean = 90 Mean = 88 Standard Deviation = 5 Standard Deviation = 6
A random sample of 120 cars in the drive-thru of a popular fast food restaurant revealed that the mean bill of $29.27 per car. The population standard deviation is $6.17. Find the mean bill for all cars from the drive-thru with 82% confidence.
Some college graduates employed full-time work more than 40 hours per week, and some work fewer than 40 hours per week. We suspect that the mean number of hours worked per week by college graduates, µ, is less than 40 hours and wish to do a statistical test. We select a random sample of college graduates employed full-time and find that the mean of the sample is 37 hours and that the standard deviation is 3 hours. Based on this information, answer the questions below. What are the null hypothesis (H,) and the alternative hypothesis (H ,) that should be used for the test? H:u is 7 In the context of this test, what is a Type I error? АТурe I error is 7 fact, u is 7 | the hypothesis that µ is ? when, in Suppose that we decide not to reject the null hypothesis. What sort of error might we be making? ?
Two estimates are available for the same population parameter. Estimate one has a standard deviation of 8.5 and estimate two has a standard deviation of 8.7. Estimate two is unbiased, whereas estimate one is biased. Which estimate would you choose and why?
Consider a set of data in which the sample mean is 30.230.2 and the sample standard deviation is 7.87.8. Calculate the z-score given that x=31.4x=31.4. Round your answer to two decimal places.

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