Chp 19 #28 & # 30 Item 3030 of 30I Review | Constants | Periodic TabMISSED THIS? Read Section19.10 (Pages 881 - 884) ; Watch IWE 19.11Finaily, exponentiate tnis vaiue to caicuiate tne equiIprium constant:K =e13.2Use AG; values from Appendix IIB to calculatethe equilibrium constants at 25 °C for each of thefollowing reactions.5.4 x 105Part BH2 (g) + P1(g) =PH3(g)Express your answer to two significant figures.• View Available Hint(s)K =Submit View Available Hint(s)kJ/molAG =

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Answered: Chp 19 #28 & # 30

Science

Chemistry

Chp 19 #28 & # 30

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Chp 19 #28 & # 30

Item 30
30 of 30
I Review | Constants | Periodic Tab
MISSED THIS? Read Section
19.10 (Pages 881 - 884) ; Watch IWE 19.11
Finaily, exponentiate tnis vaiue to caicuiate tne equiIprium constant:
K =
e13.2
Use AG; values from Appendix IIB to calculate
the equilibrium constants at 25 °C for each of the
following reactions.
5.4 x 105
Part B
H2 (g) + P1(g) =PH3(g)
Express your answer to two significant figures.
• View Available Hint(s)
K =
Submit

<Chapter 19 Homework
Item 28
Part A
Consider the following reaction:
CO2 (g) + CC4 (g)
= 2COC12 (g)
Calculate AG for this reaction at 25 °C under these conditions:
Pco,
0.140 atm
0.165 atm
Pcocl,
0.755 atm
AG for CO2(g) is –394.4 kJ/mol. AG for CC4 (g) is –62.3 kJ/mol, and AG; for COCl2 (g) is – 204.9 kJ/mol.
Express the energy change in kilojoules per mole to one decimal place.
> View Available Hint(s)
kJ/mol
AG =

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