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Choose the noble gas atoms that has the same electron configuration as each of the ions in the following compounds: BaS In progress a. OBa²+, [Kr]; S², [Xe] Ba²+, [Kr]; S², [Ar] Ba²+, [Xe]; S2, [Ar] Ba2+, [Rn]; S², [Kr] MgF2 b. Mg2+, [He]; F, [Ne] Mg2+, [Ne]; F, [Ne] Mg2+, [Ar]; F, [Ne] Mg2+, [Ar]; F, [Ar] C. Li₂O Lit, [He]; 02-, [Ar] Lit, [Ne]; 02, [Ne] Lit, [Ar]; 02, [Ar] Lit, [He]; 0², [Ne]

Choose the noble gas atoms that has the same electron configuration as each of the ions in the following compounds: BaS In progress a. OBa²+, [Kr]; S², [Xe] Ba²+, [Kr]; S², [Ar] Ba²+, [Xe]; S2, [Ar] Ba2+, [Rn]; S², [Kr] MgF2 b. Mg2+, [He]; F, [Ne] Mg2+, [Ne]; F, [Ne] Mg2+, [Ar]; F, [Ne] Mg2+, [Ar]; F, [Ar] C. Li₂O Lit, [He]; 02-, [Ar] Lit, [Ne]; 02, [Ne] Lit, [Ar]; 02, [Ar] Lit, [He]; 0², [Ne]

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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In progress [Review Topics] Choose the noble gas atoms that has the same electron configuration as each of the ions in the following compounds: BaS a. (Ba*+, [Kr]; Sả, [Xe Ba²+, [Kr]; S2, [Ar] Ba²+, [Xe]; S2, [Ar] Ba2+, [Rn]; S², [Kr] MgF2 b. Mg2+, [He]; F, [Ne] Mg2+, [Ne]; F, [Ne] Mg²+, [Ar]; F, [Ne] Mg2+, [Ar]; F, [Ar] Li₂O c. Lit, [He]; 0², [Ar] Lit, [Ne]; 02-, [Ne] Lit, [Ar]; 0², [Ar] Lit, [He]; 02, [Ne] [References]
Transcribed Image Text:In progress [Review Topics] Choose the noble gas atoms that has the same electron configuration as each of the ions in the following compounds: BaS a. (Ba*+, [Kr]; Sả, [Xe Ba²+, [Kr]; S2, [Ar] Ba²+, [Xe]; S2, [Ar] Ba2+, [Rn]; S², [Kr] MgF2 b. Mg2+, [He]; F, [Ne] Mg2+, [Ne]; F, [Ne] Mg²+, [Ar]; F, [Ne] Mg2+, [Ar]; F, [Ar] Li₂O c. Lit, [He]; 0², [Ar] Lit, [Ne]; 02-, [Ne] Lit, [Ar]; 0², [Ar] Lit, [He]; 02, [Ne] [References]
Expert Solution
Step 1

Solution - 

Electronic configuration of Barium -[Xe] 6s2 

when charge is 2+ it means it will loose 2 electrons so final electronic configuration for Ba2+= [Xe] . 

Electronic configuration of sulphur = [Ne] 3s2 3p4 . 
charge is 2- which means it gain 2 electrons 

[Ne] 3s2 3p6 . (Configuration of argon ) 

So C is correct option for a part . 

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